Hi! I need help understanding this question. Complete the statements below about the area of the red rectangle.

Mathematics

2 answers:

Anastasy [175]4 years ago

6 0

holee

Step-by-step explanation:Answer:

how bout you start off helping mhe

matrenka [14]4 years ago

3 0

there are no statements below

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Which of these is an odd function?

Yakvenalex [24]

Answer:

$f(x)=2x^3+x$

Step-by-step explanation:

An odd function <em>f</em> is one where $f(-x)=-f(x)$ . We can interpret this is meaning: reflecting the graph horizontally $f(-x)$ has the same effect as reflecting it vertically $-f(x)$ . The only graphs that meet this requirement are ones with reflectional symmetry across the line y = x, so we can immediately elimate the functions $f(x)=3x^2+7$ and $f(x)=5x^2-6$ , which have horizontal symmetry, but not the kind of symmetry we're looking for.

That leaves us with $f(x)=2x^3+x$ and $f(x)=4x^3+2x^2$ . One feature of exponents we can utilize is that -1 to an even power is 1, while -1 to an odd power is -1. If we want $f(-x)=-f(x)$ , we need to flip the signs of <em>all </em>the coefficients, and we can only do that if all the powers of x are odd. The only function with only odd powers of x is $f(x)=2x^3+x$ , and plugging in -x to the function reveals that

$f(-x)=2(-x)^3+(-x)\\f(-x)=-2x^3-x=-(2x^3+x)=-f(x)$

So $f(x)=2x^3+x$ the only odd function on the list!

3 0

3 years ago

What are the answers to these

mina [271]

Distributive property
Use multiplication to simplify
Simplify using addition
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Multiply each side by -3/4 and simplify

7 0

4 years ago

A man who moves to a new city sees that there are two routes he could take to work. A neighbor who has lived there a long time h

lawyer [7]

Answer:

The 95% confidence interval for the difference between the Route B and Route A commuting times is -3.771808 to 1.771808

Step-by-step explanation:

Here we have the confidence interval is given by the following equation;

$\left (\bar{x}_1-\bar{x}_{2} \right ) - z_{c}\sqrt{\frac{\sigma _{1}^{2}}{n_{1}}-\frac{\sigma _{2}^{2}}{n_{2}}}< \mu _{1}-\mu _{2}< \left (\bar{x}_1-\bar{x}_{2} \right ) + z_{c}\sqrt{\frac{\sigma _{1}^{2}}{n_{1}}-\frac{\sigma _{2}^{2}}{n_{2}}}$