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svetoff [14.1K]

2 years ago

8

So i need to pick classes for my freshman year next year and i d k if i should take pre algebra or just do algebra. My math grad

e right now is 3.7 out of 4

1 answer:

ahrayia [7]2 years ago

8 0

Answer:

Step-by-step explanation:

My recommendation is try to find a finals for both pre-algebra or algebra after learning some of the material ahead of time and after taking them, find which one is more comfortable for you

Good luck!

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which is the solutions to the system of equations shown { 3x - y = 6 and here is the other equation{ x - 2y = -18

Vinvika [58]

Answer:

(6, 12)

Step-by-step explanation:

{ 3x - y = 6

{ x - 2y = -18

by using elimination:

6x -2y=12

x - 2y= -18

________-

5x = 30

x = 6

y = 18-6 = 12

the solutions = {(6, 12)}

3 0

2 years ago

Can anyone help. Greatly appreciate:)

PilotLPTM [1.2K]

Answer:

Area= 12 units squared, Perimeter= 16.12899

Step-by-step explanation:

$AC= \sqrt{(4-0)^{2}+ (0+4)^{2}} = 4\sqrt{2}$

$AB= \sqrt{(0-4)^{2}+ (2-0)^{2} } = 2\sqrt{5}$

$BC= \sqrt{(0-0)^{2}+ (2+4)^{2} }= 6$

So, perimeter= $4\sqrt{2} + 2\sqrt{5} +6= 16.12899$

$Area= \frac{1}{2}bh\\$

$= \frac{1}{2}BC\sqrt{(4-0)^{2}+(0-0)^{2} }$

$= 12$ $units^{2}$

6 0

3 years ago

Please show all work for this <br> 7x + 3 =9x - 7

luda_lava [24]

<u>7x + 3 = 9x - 7</u>

Subtract 7x from each side: + 3 = 2x - 7

Add 7 to each side: 10 = 2x

Divide each side by 2 : <em>5 = x </em>

8 0

3 years ago

Express x^2-8+5 in the form (x-a)^2-b where a and b are integers

Tanzania [10]

Answer:

(x-4)^2-9 where a=4 and b=9

Step-by-step explanation:

x^2-8x+5

x^2-8x+16-16+5

(x-4)^2-9, a=4 and b=9

6 0

3 years ago

Suppose a, b denotes of the quadratic polynomial x² + 20x - 2022 & c, d are roots of x² - 20x + 2022 then the value of ac(a

Alja [10]

<h3><u>Correct Question :- </u></h3>

$\sf\:a,b \: are \: the \: roots \: of \: {x}^{2} + 20x - 2020 = 0 \: and \: \\ \sf \: c,d \: are \: the \: roots \: of \: {x}^{2} - 20x + 2020 = 0 \: then \:$

$\sf \: ac(a - c) + ad(a - d) + bc(b - c) + bd(b - d) =$

(a) 0

(b) 8000

(c) 8080

(d) 16000

$\large\underline{\sf{Solution-}}$

Given that

$\red{\rm :\longmapsto\:a,b \: are \: the \: roots \: of \: {x}^{2} + 20x - 2020 = 0}$

We know

$\boxed{\red{\sf Product\ of\ the\ zeroes=\frac{Constant}{coefficient\ of\ x^{2}}}}$

$\rm \implies\:ab = \dfrac{ - 2020}{1} = - 2020$

And

$\boxed{\red{\sf Sum\ of\ the\ zeroes=\frac{-coefficient\ of\ x}{coefficient\ of\ x^{2}}}}$

$\rm \implies\:a + b = - \dfrac{20}{1} = - 20$

Also, given that

$\red{\rm :\longmapsto\:c,d \: are \: the \: roots \: of \: {x}^{2} - 20x + 2020 = 0}$

$\rm \implies\:c + d = - \dfrac{( - 20)}{1} = 20$

and

$\rm \implies\:cd = \dfrac{2020}{1} = 2020$

Now, Consider

$\sf \: ac(a - c) + ad(a - d) + bc(b - c) + bd(b - d)$

$\sf \: = {ca}^{2} - {ac}^{2} + {da}^{2} - {ad}^{2} + {cb}^{2} - {bc}^{2} + {db}^{2} - {bd}^{2}$

$\sf \: = {a}^{2}(c + d) + {b}^{2}(c + d) - {c}^{2}(a + b) - {d}^{2}(a + b)$

$\sf \: = (c + d)( {a}^{2} + {b}^{2}) - (a + b)( {c}^{2} + {d}^{2})$

$\sf \: = 20( {a}^{2} + {b}^{2}) + 20( {c}^{2} + {d}^{2})$

$\sf \: = 20\bigg[ {a}^{2} + {b}^{2} + {c}^{2} + {d}^{2}\bigg]$

We know,

$\boxed{\tt{ { \alpha }^{2} + { \beta }^{2} = {( \alpha + \beta) }^{2} - 2 \alpha \beta \: }}$

So, using this, we get

$\sf \: = 20\bigg[ {(a + b)}^{2} - 2ab + {(c + d)}^{2} - 2cd\bigg]$

$\sf \: = 20\bigg[ {( - 20)}^{2} + 2(2020) + {(20)}^{2} - 2(2020)\bigg]$

$\sf \: = 20\bigg[ 400 + 400\bigg]$

$\sf \: = 20\bigg[ 800\bigg]$

$\sf \: = 16000$

Hence,

$\boxed{\tt{ \sf \: ac(a - c) + ad(a - d) + bc(b - c) + bd(b - d) = 16000}}$

<em>So, option (d) is correct.</em>

4 0

2 years ago