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Debora [2.8K]
4 years ago
11

If the number of bacteria in a colony doubles every 400 hours and there is currently a population of 500 bacteria, what will the

population be 800 hours from now?
Mathematics
1 answer:
stiv31 [10]4 years ago
3 0

Answer:

2000 bacterias

suppose, x is the bacteria

there are 500x . for the first 400 hours,the 500 x will double which gives=

500x2=1000 bacterias

then the next 400 hours,the 1000x will double which gives=

1000x2=2000 bacterias

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Twenty-five members of the eighth grade class at Park Center Middle School are going to a museum and then to lunch. Each student
Damm [24]
There are two costs involved:

1) the cost for lunch, which is given as a rate per student: $7.25/student

2) the cost for the trip which is $443.75 to be divided by the 25 students, so it is $443.75 / 25 = $17.75/student

Now, you can add up those two costs per student to have the total cost per student:

$7.25 + $17.75 = $25.00/student

Answer: $25.00
5 0
4 years ago
Read 2 more answers
A cheetah can travel 112.5 mi in 1.5 hours at what rate does a cheetah travel
trapecia [35]

Answer:

75 mph

Step-by-step explanation:

To find the rate of speed you have to divide 112.5 by 1.5 and the answer its 75 miles per hour.

4 0
3 years ago
The sides of square ABCD .. (photo provided)
atroni [7]

There are in fact two methods to solve this problem which I will show below:

(1) Knowing that the area of square ABCD is 144 cm^2, we can calculate the side lengths as the area of a square is given by the length of one of its sides squared, thus:
144 = l^2
l = 12 cm

Now we can take a length, let's say AD and we know that it is 12 cm; we also know that MA is 6 cm, so MD would be 18 cm.
HD = MA = 6 cm
Triangle MDH is a right-angled triangle so we can use Pythagoras' theorem (c^2 = a^2 + b^2) to solve for length MH, thus:

MH^2 = 6^2 + 18^2
MH = sq.root(360)
= 6 sq.root(10)

Now that we know the length of one of the sides of the larger square we can square it to obtain the area:

Area = (6 sq.root(10))^2 = 360 cm^2

(2) After calculating that the side length of square ABCD is 12 cm, MD is 18 cm and HD is 6 cm, we can find the area of triangle MDH using the formula below:

Area = 0.5*bh
= 0.5*6*18
= 54 cm^2

Now looking at the diagram you can actually see that there are four of these triangles (MDH, MAW, WBT and HCT) and so if we multiply the area of one of the triangles by four we can find the area of the larger square that is not occupied by the smaller square, thus:

Area = 54*4 = 216 cm^2

Now we can add this together with the area of the smaller square to get:

Area of larger square = 216 + 144 = 360 cm^2

Thus in either case the answer would be A. Hope that helps :)
5 0
4 years ago
The bus fare in a city is People who use the bus have the option of purchasing a monthly coupon book for With the coupon​ book,
Mekhanik [1.2K]

Answer:

21

Step-by-step explanation:

The bus fare in a city is $1.50. People who use the bus have the option of purchasing a monthly coupon book for $21.00. With the coupon book, the fare is reduced to $0.50. Determine the number of times in a month the bus must be used so that the total monthly cost without the coupon book is the same as the total monthly cost with the coupon book.

Solution

Let

y = number of bus fares.

Cost of bus fares without coupon book = 1.50y

Cost of bus fares with coupon book = .50y + 21

Equate cost of bus fares without coupon book and cost of bus fares with coupon book

1.50y = .50y + 21

Subtract .50y from both sides of the equation

1.50y - .50y = .50y + 21 - .50y

1.00y = 21

Divide both sides by 1.00

y = 21 / 1.00

y = 21 times

4 0
3 years ago
Assume that when with smartphones are randomly selected, 46% use them in meetings or classes. If 12 adult smartphone users are r
stellarik [79]

Answer:

The probability that fewer than 3 of them use their smartphones in meetings or classes is 0.03634

Step-by-step explanation:

Apply binomial probability formula which is written as;

P(X=x)=\frac{n!}{x!(n-x)!} *P^{x} *(1-P)^{n-x}

where P=46% =0.46, n=12

For this case where you find the probability that fewer than 3 of them use their smartphones in meeting or classes, x=2,1,0

Evaluating binomial probability at x=2 will be;

P(X=2)=\frac{12!}{2!(12-2)!} *0.46^2*(1-0.46)^{12-2} \\\\P(X=2)=\frac{12!}{2!10!} *0.2116*0.002108\\\\=66*0.2116*0.002108\\=0.02944

P(X=2)=0.02944

Evaluate binomial probability at x=1

P(X=1)=\frac{12!}{1!(12-1)!} *0.46^1*(1-0.46)^{12-1} \\\\P(X=1)=\frac{12!}{1!11!} *0.46*0.54^{11} \\\\P(X=1)=12*0.46*0.001138\\\\P(X=1)=0.006284

P(X=1)= 0.006284

Evaluate binomial probability at x=0

P(X=0)=\frac{12!}{0!(12-0)!} *0.46^0*(1-0.46)^{12-0} \\\\P(X=0)=\frac{12!}{1*12!} *0.46^0*0.54^{12} \\\\P(X=0)=1*1*0.0006148 =0.0006148

P(X=0)=0.0006148

Now for P(X<3)=P(X=2)+P(X=1)+P(X=10) =0.02944+0.006284+0.0006148

=0.0363388

=0.03634 (in 4 significant figures)

4 0
3 years ago
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