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maxonik [38]
3 years ago
15

Consider a ball rolling down the decreasing slope inside a semicircular bowl (the slope is steep at the top rim, gets less steep

toward the bottom, and is zero (no slope) at the bottom). As the ball rolls from the rim downward toward the bottom, its rate of gaining speed
Physics
1 answer:
satela [25.4K]3 years ago
8 0
The answer would be:
<span>It's rate of gaining speed decreases.
The rate at which speed changes is called acceleration, 
You can think of this problem as an inclined plane. But the angle of an inclined plane is constantly decreasing.
We know that on a frictionless inclined plane acceleration of an object is:
</span>a=gsin(\theta)
<span>Where g is the gravitational acceleration of the Earth and \theta is the angle of an inclined plane. 
Using our analogy, the ball would start on an inclined plane with a 90-degree angle and that angle would continue to decrease to zero. 
The sine function is 1 at 90 degrees and is equal to zero at 0 degrees. Since our acceleration is proportional to the sine, and sine function is decreasing with the angle, our acceleration is also decreasing.

</span>
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How far apart must two protons be if the electrical force acting on either one is equal to its weight on the earth's surface whe
BARSIC [14]

Answer:

G M m / R^2 = F   force of attraction for proton

K e^2 / r^2 = F     force of attraction between 2 protons

G M m / R^2 = K e^2 / r^2

r^2 = K e^2 R^2 / (G M m)

r^2 = 9E9 * (1.6E-19)^2 * (6.37E6)^2 / (6.67E-11 * 5.98E24 * 1.7E-27)

r^2 = 9 * 2.56 * 40.6 / (6.67 * 5.98 * 1.7) * 10^-19

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7 0
3 years ago
Which one is better yoga or exercise?
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Yoga because It brings together physical and mental disciplines to achieve a peaceful body and mind; it helps manage stress and anxiety and keeps you relaxing and exercising just builds muscles

Explanation:

have great day!

8 0
2 years ago
In a Rutherford scattering experiment a target nucleus has a diameter of 1.34×10-14 m. The incoming α particle has a mass of 6.6
Rasek [7]

Answer:

E = 2.5 x 10⁻¹⁴ J

Explanation:

given,

diameter = 1.33 x 10⁻¹⁴ m

mass = 6.64 x 10⁻²⁷ kg

wavelength is equal to diameter

de broglie wavelength equal to diameter

         \lambda = \dfrac{h}{mv}

         1.33 \times 10^{-14}= \dfrac{6.626 \times 10^{-34}}{6.64 \times 10^{-27}\times v}

         v= \dfrac{6.626 \times 10^{-34}}{6.64 \times 10^{-27}\times 1.33 \times 10^{-14}}

              v = 7.5 x 10⁶ m/s

Kinetic energy is equal to

     E = \dfrac{1}{2}mv^2

     E = \dfrac{1}{2}\times 6.64 \times 10^{-27}\times (7.5\times 10^6)^2

            E = 2.5 x 10⁻¹⁴ J

8 0
3 years ago
The spreading of waves behind an aperture ismore for long wavelengths and less for short wavelengths.less for long wavelengths a
kompoz [17]
<h2>Answer: The spreading of waves behind an aperture ismore for long wavelengths and less for short wavelengths</h2>

Here we are talking about Diffraction and, in fact, waves diffract the most when their wavelength is about the same size of the gap or aperture.

Diffraction happens when a wave (mechanical or electromagnetic wave) meets an obstacle or a slit .When this occurs, <u>the wave bends around the corners of the obstacle or passes through the opening of the slit that acts as an obstacle, forming multiple patterns with the shape of the aperture of the slit. </u>

<u />

Note that the principal condition for the occurrence of this phenomena is that the obstacle must be comparable in size (similar size) to the size of the wavelength.

In other words, when the gap (or slit) size is larger than the wavelength, the wave passes through the gap and does not spread out much on the other side, but when the gap size is equal to the wavelength, maximum diffraction occurs and the waves spread out greatly.

This means the smaller the slit or obstacle (diffracting object), the wider the resulting diffraction pattern, and the greater the obstacle, the narrower de resulting patter.

6 0
3 years ago
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