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Sonja [21]
3 years ago
14

The spreading of waves behind an aperture ismore for long wavelengths and less for short wavelengths.less for long wavelengths a

nd more for short wavelengths.the same for long and short wavelengths.not discussed in this chapter.
Physics
1 answer:
kompoz [17]3 years ago
6 0
<h2>Answer: The spreading of waves behind an aperture ismore for long wavelengths and less for short wavelengths</h2>

Here we are talking about Diffraction and, in fact, waves diffract the most when their wavelength is about the same size of the gap or aperture.

Diffraction happens when a wave (mechanical or electromagnetic wave) meets an obstacle or a slit .When this occurs, <u>the wave bends around the corners of the obstacle or passes through the opening of the slit that acts as an obstacle, forming multiple patterns with the shape of the aperture of the slit. </u>

<u />

Note that the principal condition for the occurrence of this phenomena is that the obstacle must be comparable in size (similar size) to the size of the wavelength.

In other words, when the gap (or slit) size is larger than the wavelength, the wave passes through the gap and does not spread out much on the other side, but when the gap size is equal to the wavelength, maximum diffraction occurs and the waves spread out greatly.

This means the smaller the slit or obstacle (diffracting object), the wider the resulting diffraction pattern, and the greater the obstacle, the narrower de resulting patter.

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ohaa [14]

Answer:

C ) 1.53

Explanation:

The critical angle of a material is given by the formula

sin c = \frac{1}{n}

where

c is the critical angle

n is the refractive index

This formula is valid if the second medium is air (which is the case of the problem).

In this problem, we know the critical angle:

c=40.8^{\circ}

Therefore we can rearrange the equation to find the refractive index:

n=\frac{1}{sin c}=\frac{1}{sin 40.8^{\circ}}=1.53

5 0
3 years ago
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Explanation:

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