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4 years ago

An electric circuit can have no current when a switch is .

Physics

2 answers:

Korolek [52]4 years ago

7 0

Answer: It's "Open"

Explanation:

Stells [14]4 years ago

3 0

An electric current can have no current when the switch is OPEN

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A body of mass 3 kg and volume 4 x 10^m' is hung from a balance

motikmotik

Answer:

it's b I guess not sure

Explanation:

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3 years ago

1. Place the following taxonomic groups in order, from largest to smallest: class, domain, family, genus, kingdom, order, phylum

sesenic [268]

1. Domain, kingdom, phylum, class, order, family, genus, species, and subspecies.

2. If a variety of the species with a certain gene is vulnerable to a specific disease, predator, or environmental development, other members of the species with variants of the gene may be better equipped to handle the problem, and the species won't die out, just a portion of the disadvantaged.

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3 years ago

Read 2 more answers

The number density of gas atoms at a certain location in the space above our planet is about 1.05 × 1011 m-3, and the pressure i

Anettt [7]

To solve this problem we will apply the concepts given by the ideal gas equation, which mathematically can be described as

$PV = NkT$

Here

P = Pressure

V = Volume

N = Number of atoms of molecules

k = Bolzmann constant

T = Temperature

Rearranging to find the temperature we have

$T = \frac{PV}{Nk}$

Since the value given in the exercise is a unit of atoms per volume, we will readjust the equation like this

$T = \frac{P}{\frac{N}{V}k}$

Replacing we have,

$T = \frac{(2.7*10^{-10}N/m^2)}{(1.05*10^{11}/m^3)(1.38*10^{-23}J/K)}$

$T = 186.3K$

$T = -86.81\°C$

Therefore the temperature is -86.81°C or 186.3K

7 0

4 years ago

A street musician sounds the A string of his violin, producing a tone of 440 Hz, What frequency does a bicyclist hear as he a) a

DanielleElmas [232]

Answer:

a) $f_o=454.11Hz$

b) $f_o=425.89Hz$

Explanation:

Let´s use Doppler effect, in order to calculate the observed frequency by the byciclist. The Doppler effect equation for a general case is given by:

$f_o=\frac{v\pm v_o}{v\pm v_s} *f_s$

where:

$f_o=Observed\hspace{3}frequency$

$f_s=Actual\hspace{3}frequency$

$v=Speed\hspace{3}of\hspace{3}the\hspace{3}sound\hspace{3}waves$

$v_s=Velocity\hspace{3}of\hspace{3}the\hspace{3}source$

$v_o=Velocity\hspace{3}of\hspace{3}the\hspace{3}observer$

Now let's consider the next cases:

$+v_o\hspace{3}is\hspace{3}used\hspace{3}when\hspace{3}the\hspace{3}observer\hspace{3}moves\hspace{3}towards\hspace{3}the\hspace{3}source$

$-v_o\hspace{3}is\hspace{3}used\hspace{3}when\hspace{3}the\hspace{3}observer\hspace{3}moves\hspace{3}away\hspace{3}from\hspace{3}the\hspace{3}source$

$-v_s\hspace{3}is\hspace{3}used\hspace{3}when\hspace{3}the\hspace{3}source\hspace{3}moves\hspace{3}towards\hspace{3}the\hspace{3}observer$

$+v_s\hspace{3}is\hspace{3}used\hspace{3}when\hspace{3}the\hspace{3}source\hspace{3}moves\hspace{3}away\hspace{3}from\hspace{3}the\hspace{3}observer$

The data provided by the problem is:

$f_s=440Hz\\v_o=11m/s$

The problem don't give us aditional information about the medium, so let's assume the medium is the air, so the speed of sound in air is:

$v=343m/s$

Now, in the first case the observer alone is in motion towards to the source, hence:

$f_o=\frac{v+v_o}{v}*f_s=\frac{343+11}{343} *440=454.1107872Hz$

Finally, in the second case the observer alone is in motion away from the source, so:

$f_o=\frac{v-v_o}{v}*f_s=\frac{343-11}{343} *425.8892128Hz$

6 0

4 years ago

A physics major is cooking breakfast when he notices that the frictional force between his steel spatula and his Teflon frying p

MrRissso [65]

Answer:5 N

Explanation:

Given

A physics major is cooking breakfast when he notices that the frictional force between his steel spatula and his Teflon frying pan is only 0.200 N

And from tables of coefficient of Kinetic friction for Teflon is $\nu _k=0.04$

and Friction force is $\nu N$

where N is the normal reaction

$N=\frac{0.200}{0.04}=5 N$

6 0

4 years ago