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Aleks04 [339]
3 years ago
9

A ball is thrown upward from an initial height of 1.5m the ball reaches a height of 5m then falls to the ground . What Is the di

stance traveled by the ball?
Physics
1 answer:
jeka943 years ago
4 0

Answer:

The distance traveled by the ball is 8.5 m

Explanation:

Initial height of the ball, h₁ = 1.5 m above the ground

final height of the ball, h₂ = 5m

Upward distance = distance traveled by the ball from a height of 1.5m to 5m = 5m - 1.5m = 3.5 m

Downward distance = distance traveled by the ball from 5m height to the ground =5m - 0 = 5m

Total distance traveled = upward distance + downward distance

Total distance traveled = 3.5 m + 5m = 8.5 m

Therefore, the distance traveled by the ball is 8.5 m

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It is often revealed <span>at the resolution of the story, when the reader can see how the story ends.</span>
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Which one of the following temperatures (in °C) is equivalent to 294 K?
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Answer:

21

Explanation: its actually 20.85 but i guess they round to 21

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2 years ago
Find the minor measurement of the vernier scale by taking 49, 1mm divisions of the main scale and dividing it into 50 vernier di
olga nikolaevna [1]
<h2>♨ANSWER♥</h2>

length of V-50 = 49mm

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2 years ago
Suppose that a comet has a very eccentric orbit that brings it quite close to the Sun at closest approach (perihelion) and beyon
Nutka1998 [239]

Answer:

16.63min

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The question is about the period of the comet in its orbit.

To find the period you can use one of the Kepler's law:

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M: mass of the sun = 1.99*10^30 kg

By replacing you obtain:

T=\sqrt{\frac{4\pi}{GM}r^3}=\sqrt{\frac{4\pi^2}{(6.67*10^{-11}Nm^2/kg^2)(1.99*10^{30}kg)}(1.496*10^8m)^3}\\\\T=997.9s\approx16.63min

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8 0
3 years ago
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Answer:

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area = a*b

area = 3.2m * 8.01m

area = 25.632 m²

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3 years ago
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