Ask question

Ask question

All categories

3 years ago

15

What is the solution to the equation

le="2x - 7 = 6x + 1" alt="2x - 7 = 6x + 1" align="absmiddle" class="latex-formula">

2 answers:

guajiro [1.7K]3 years ago

7 0

Answer:

;lkjjjhhghhhhhhhiokjml,.

Step-by-step explanation:

IgorC [24]3 years ago

3 0

2x-6x=1+7
-4x=8
-x=2
x=-2
Hope this can help.

You might be interested in

4(x+2)=30 <br> I need help

mars1129 [50]

Answer:

x = 11/2

Step-by-step explanation:

8 0

4 years ago

I have 7 hundreds blocks, 5 tens blocks, and 8 ones blocks. I use my blocks to model two 3-digit numbers. What could my two numb

lawyer [7]

There 7 blocks of hundreds which means each such block is equivalent to 100.
There are 5 blocks of tens, which means each such block is equivalent to 10.
There are 8 blocks of ones, which means each such block is equivalent to 1.

The total of these blocks will be = 7(100) + 5(10) + 8(10) = 758

We can make several two 3-digit numbers from these blocks. An example is listed below:

Example:
Using 3 hundred block, 2 tens blocks and 4 ones block to make one number and remaining blocks to make the other number. The remaining blocks will be 4 hundred blocks, 3 tens blocks and 4 ones blocks
The two numbers we will make in this case are:

1st number = 3(100) + 2(10) + 4(1) = 324
2nd number = 4(100) + 3(10) + 4(1) = 434

The sum of these two numbers is = 324 + 434 = 758
i.e. equal to the original sum of all blocks.

This way changing the number of blocks in each place value, different 3 digit numbers can be generated.

5 0

3 years ago

Find all solutions of the equation in the interval [0,2pi)<br> 8sec^2x+4tan^2x-12=0

andrezito [222]

Π/6+2πk
5π/6+2πk
you need to factor and use trig identities

6 0

3 years ago

Read 2 more answers

Completing the square Acellus please help! x^2 + 10x -y + 15 = 0 <br><br>Thank you!!

klemol [59]

Step-by-step explanation:

y-15=x^2+10x

y-15+25=x^2+10x+25

y+10=(x+5)^2

7 0

3 years ago

Negate verbally:

ohaa [14]

Answer:

Negate verbally: (a) Some people weigh 100 pounds

(B) Everybody did see many animals in the zoo.

Step-by-step explanation:

Consider the provided information.

Negate rules:

For Particular Quantifier:

There exists some, Some, Few, etc

Negate them with Universal Quantifiers like:

Everyone, All, Many, For All, etc.

For Universal Quantifiers:

Everyone, All, Many, For All, etc.

Negate them with Particular Quantifiers like

There exists some, Some, Few, etc

Part (A): "All people weigh at least 100 pounds."

We can negate it as: "Some people weigh 100 pounds"

Part (B) "Somebody did not see any animals in the zoo"

We can negate it as: "Everybody did see many animals in the zoo."

3 0

3 years ago