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3 years ago

12

Help!!! I’m bad at Math!

2 answers:

ollegr [7]3 years ago

8 0

3) -0.84, -0.32, 0.32, 0.84
4) -4/9, -1/3, 2/9, 1/3

e-lub [12.9K]3 years ago

6 0

-0.84 , -0.32, 0.32, 0.84

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In 217,534,896,000,000 which digit is in the ten-billions place

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3 is the 10 billions place

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How do I factor e^2-10e+25

olga nikolaevna [1]

Answer: (e-5)^2

Step-by-step explanation:

The box method is a good way to solve this, but for a quick explanation, start by finding a single value that when added gets -10 and when multiplied gets +25. We can find that this term is -5. We the can situate -5 into (e-5)^2 equation, where if you FOIL, you will be back at the unfactored equation. Hope this helps

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The product of (4z^2 + 7z - 8) and (-z + 3) is -4z^3 + xz^2 + yz - 24. What is the value of x? What is the value of y?

ycow [4]

Answer:

$x=5+\frac{29}{z}-\frac{y}{z}$

$y=5z+29-xz$

Step-by-step explanation:

Given: $(4z^2+7z-8)(-z+3)=-4z^3+xz^2+yz-24$ ; find x and y.

Let's start with finding x first. Let's distribute the left side of the equation.

$-4z^3+5z^2+29z-24=-4z^3+xz^2+yz-24$

Let's move everything we can to the left side of the equation. Some things will cancel out.

$5z^2+29z=xz^2+yz$

Now, let's move the term that includes $x$ to the left side of the equation. Everything else should be moved to the right.

$-xz^2=-5z^2-29z+yz$

Let's get rid of the negative sign in front of $x$ by dividing both sides by -1.

$xz^2=5z^2+29z-yz$

To get $x$ completely isolated, divide both sides by $z^2$ .

$\frac{xz^2}{z^2}=\frac{5z^2}{z^2}+\frac{29z}{z^2}-\frac{yz}{z^2}$

Simplify.

$x=5+\frac{29}{z}-\frac{y}{z}$

Let's solve for y. We will start with the distributed and simplified equation to make it easier.

$5z^2+29z=xz^2+yz$

Now, let's move the term that includes $y$ to the left side of the equation. Everything else should be moved to the right.

$-yz=-5z^2-29z+xz^2$

Again, let's get rid of the negative sign in front of the $y$ by dividing both sides by -1.

$yz=5z^2+29z-xz^2$

To isolate y, divide both sides by z.

$\frac{yz}{z}=\frac{5z^2}{z}+\frac{29z}{z}-\frac{xz^2}{z}$

Simplify.

$y=5z+29-xz$

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