According to the question,

$x +y=30~~~~......equation (1)\\xy=176~~~~........equation (2)\\\\Taking~equation~(2),\\ xy=176\\\\y = \frac{176}{x}\\\\Now, ~substuting~the~value~of~y~in~equation~(1), ~we~get,\\\\x+ \frac{176}{x}=30\\\\ \frac{x^2+176}{x}=30\\\\x^2+176=30x\\\\x^2-30x+176=0\\\\x^2-8x-22x+176=0\\\\x(x-8)-22(x-8)=0\\\\(x-8)(x-22)=0\\\\Using~zero~product~property,\\\\Either, \\x-8=0\\x=8\\\\Or,\\ x-22=0 \\x=22\\\\When,\\x=8,\\\\(8)+y=30\\y=22 \\\\And~when,\\x=22\\\\(22)+y=30\\y=8\\ \therefore The~two~numbers~are~8~and ~22$

6 0

4 years ago

Anyone 100% know dis answer

siniylev [52]

Answer:

Rotational symmetry

Step-by-step explanation:

The rectangle rotated 180 degrees to get the transformed rectangle.

4 0

3 years ago

What is the focus of the parabola given by the equation y = x2 − 2x − 3?

erica [24]

What is the focus of the parabola given by the equation y = x2 − 2x − 3?
y = x2 − 2x − 3
y = x2 − 2x − 3 -1 +1y = (x - 1)^2 - 4 h = 1 and k = - 4 and a = 1

Vertex (a, k) so it is (1,-4)

Now focus is
(1, -4 + 1/4) = (1,-3 3/4)
or
(1,-3.75)

4 0

3 years ago