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2 years ago

In which number does the digit 8 have a value that is 1,000 times greater than the digit 8 in the number 349,257.83?

Mathematics

1 answer:

Makovka662 [10]2 years ago

8 0

Answer:

349,257,830

Step-by-step explanation:

Multiply 349,257.83 by 1000

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2 years ago

At an effective annual interest rate of i > 0, each of the following two sets of payments has present value K: (i) A payment

IgorLugansk [536]

Answer:

The present value of K is, $K=251.35$

Step-by-step explanation:

First of all, we need to construct an equation system, so

$(1)K=\frac{169}{(1+i)} +\frac{169}{(1+i)^{2}}$

$(2)K=\frac{225}{(1+i)^{2}} +\frac{225}{(1+i)^{4}}$

Then we equalize both of them so we can find $i$

$(3)\frac{169}{(1+i)} +\frac{169}{(1+i)^{2}}=\frac{225}{(1+i)^{2}} +\frac{225}{(1+i)^{4}}$

To solve it we can multiply $(3)*(1+i)^{4}$ to obtain $(1+i)^{4}*(\frac{169}{(1+i)} +\frac{169}{(1+i)^{2}}=\frac{225}{(1+i)^{2}} +\frac{225}{(1+i)^{4}})$ , then we have $225(1+i)^{2}+225=169(1+i)^{3}+169(1+i)^{2}$ .

This leads to a third-grade polynomial $169i^{3}+451i^{2}+395i-112=0$ , after computing this expression, we find only one real root $i=0.2224$ .

Finally, we replace it in (1) or (2), let's do it in (1) $K=\frac{169}{(1+0.2224)} +\frac{169}{(1+0.2224)^{2}}\\\\K=251.35$

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3 years ago

Please answer thank you

Nina [5.8K]

If x is equaled to 10 then you will place 10 into 3 and it would look like this 3(10) + 5y= 20 now your next step is to multiply 3•10=30 so 30+5y=20 now all you have to do is 20- (-30)= -10 and then divide by 5 and it’s equal to -10/5= -2

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2 years ago