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2 years ago

A square number whose digits add up to seven.

Mathematics

2 answers:

ZanzabumX [31]2 years ago

8 0

Answer:

list the squares

1x1=1

2x2=4

3x3=9

4x4=16

16 the answer because 1+6=7

hope this helps if you have any questions you can ask

Step-by-step explanation:

Marianna [84]2 years ago

3 0

Answer:

4's square number : 16

5's square number : 25

32's square number : 1024

40's square number : 1600

49's square number : 2401

50's square number : 2500

Step-by-step explanation:

I might have missed a few but ...

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2 years ago

Find the midpoint of the line segment with endpoints at the given coordinates (-6,6) and (-3,-9)

JulsSmile [24]

The midpoint of the line segment with endpoints at the given coordinates (-6,6) and (-3,-9) is $\left(\frac{-9}{2}, \frac{-3}{2}\right)$

<u>Solution:</u>

Given, two points are (-6, 6) and (-3, -9)

We have to find the midpoint of the segment formed by the given points.

The midpoint of a segment formed by $\left(\mathrm{x}_{1}, \mathrm{y}_{1}\right) \text { and }\left(\mathrm{x}_{2}, \mathrm{y}_{2}\right)$ is given by:

$\text { Mid point } \mathrm{m}=\left(\frac{x_{1}+x_{2}}{2}, \frac{y_{1}+y_{2}}{2}\right)$

$\text { Here in our problem, } x_{1}=-6, y_{1}=6, x_{2}=-3 \text { and } y_{2}=-9$

Plugging in the values in formula, we get,

$\begin{array}{l}{m=\left(\frac{-6+(-3)}{2}, \frac{6+(-9)}{2}\right)=\left(\frac{-6-3}{2}, \frac{6-9}{2}\right)} \\\\ {=\left(\frac{-9}{2}, \frac{-3}{2}\right)}\end{array}$

Hence, the midpoint of the segment is $\left(\frac{-9}{2}, \frac{-3}{2}\right)$

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3 years ago

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Answer:

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Step-by-step explanation:

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This is the way

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Read 2 more answers

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Answer:

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Step-by-step explanation:

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