Answer:
t = 1.107
Step-by-step explanation:
Finding the solution using derivatives involves finding the lower zero of the quadratic that is the second derivative of the given function. That second derivative will be ...
f''(t) = 12(1.6714)t^2 -6(22.45)t +2(62.27)
= 20.0568t^2 -134.7t +124.54
= 20.0568(t -3.35796)² -101.619 . . . . rewrite to vertex form
Then f''(t) = 0 when ...
t ≈ 3.35796 -√(101.619/20.0568) ≈ 1.10706
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The solution is perhaps more easily found using a graphing calculator to find the peak of the first derivative. (See attached.) It tells us ...
t ≈ 1.107
1.1 years after the beginning of 1998 is about 1.2 months into 1999.
Rents were increasing most rapidly in early February of 1999.
Answer: z=0
Step-by-step explanation:
W=zr-2zt^3
Move all terms containing z to the left, all other terms to the right.
dd '-1rz' to each side of the equation.
-1rz+z=rz+-1rz+-2t^3z
Combine like terms: rz + -1rz = 0
-1rz+z=0+(-2t^3z)
-1rz+z=-2t^3z
Add 2t^3z to each side
-1rz+2t^3z+z=-2t^3z+2t^3z
Combine the like terms 2t^3z+2t^3z=0
-1rz+2t^3z+z=0
Factor out the Greatest Common Factor (GCF), 'z'.
z(-1r+2t^3+1)=0
Hope this helps, HAVE A BLESSED AND WONDERFUL DAY! As well as a great Superbowl Weekend! :-)
- Cutiepatutie ☺❀❤
Answer:
X >>>>> Y
–1 >>>> 16
0 >>>>> 8
1 >>>>> 4
2 >>>>> 2
3 >>>>> 1
Step-by-step explanation:
From the question given above,
y = 8 × (½)ˣ
When x = –1, y =?
y = 8 × (½)ˣ
y = 8 × (½)¯¹
y = 8 × 2
y = 16
When x = 1, y =?
y = 8 × (½)ˣ
y = 8 × (½)¹
y = 8 × ½
y = 4
When x = 2, y =?
y = 8 × (½)ˣ
y = 8 × (½)²
y = 8 × ¼
y = 2
When x = 3, y =?
y = 8 × (½)ˣ
y = 8 × (½)³
y = 8 × ⅛
y = 1
SUMMARY:
X >>>>> Y
–1 >>>> 16
0 >>>>> 8
1 >>>>> 4
2 >>>>> 2
3 >>>>> 1
Answer:
Yes
Step-by-step explanation:
