Answer:
81.76in^2
Step-by-step explanation:
Given data
Lenght of book= 11.2 inches
WIdth of book= 7.3 inches
We know that Area= Length* Width
Area= 11.2*7.3
Area= 81.76 in^2
Hence the area of the front of the book is is 81.76in^2
Answer:
5abc^2/35a^3c^3
Step-by-step explanation:
To bring the fraction: b/7a^2c to a denominator of 35a^3c^3, find the dividend when the 35a^3c^3 is divided by 7a^2c
=35a^3c^3/ 7a^2c
Recall that
a^x/a^y = a^x-y
Hence
35a^3c^3/ 7a^2c = 5a^3-2c^3-1
= 5ac^2
Now multiply the numerator and denominator by the result
b/7a^2c = (b * 5ac^2)/(7a^2c * 5ac^2)
Recall that
a^x * a^y = a^x+y
Hence
b/7a^2c = (b * 5ac^2)/(7a^2c * 5ac^2) = 5abc^2/35a^3c^3
I am sure it's One Solution
21 divided by 7 equals 3 and 3 x 7 is 21 the missing factor is 3 and the missing quotient is 21