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Nuetrik [128]
3 years ago
9

Avery uses a blend of dark chocolate and milk chocolate to make the ice cream topping at her restaurant. She wants to buy 10 kg

10kg10, start text, k, g, end text more of dark chocolate than milk chocolate, and she needs 150 kg 150kg150, start text, k, g, end text of chocolate in total for her next order. Let d dd be the number of kilograms of dark chocolate he buys and m mm be the number of kilograms of milk chocolate she buys. Which system of equations represents this situation?
Mathematics
1 answer:
Ksju [112]3 years ago
5 0

Answer:

d = m + 10\\d+m=150

Step-by-step explanation:

If Avery wants the amount of dark chocolate (d) to be 10 kg higher than the amount of milk chocolate (m), then the following relationship must be true:

d = m + 10

If the total amount of chocolate must equal 150 kg, then:

d+m=150

The system of equations that represent this situation is:

d = m + 10\\d+m=150

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Step-by-step explanation:

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Arc length =\int_0^{\pi} \sqrt{1+[(4.5sin(4.5x))]^2}\ dx

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Step-by-step explanation:

The arc length of the curve is given by \int_a^b \sqrt{1+[f'(x)]^2}\ dx

Here, f(x)=\int_0^{4.5x}sin(t) \ dt interval [0, \pi]

Now, f'(x)=\frac{\mathrm{d} }{\mathrm{d} x} \int_0^{4.5x}sin(t) \ dt

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\int_0^{\pi} \sqrt{1+[(4.5sin(4.5x))]^2}\ dx

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