What is your question about that?
Imagine a right triangle where a and b are the legs and c is the hypothenuse.
Pitagora: a²+b²=c²
Divide by c
(a/c)²+(b/c)²=1
But a/c=sin(B) and b/c=cos(B)
Thus sin² + cos² = 1
Answer:
The steps are more or less the same, except for one new addition:
1. Divide the tens column dividend by the divisor.
2. Multiply the divisor by the quotient in the tens place column.
3. Subtract the product from the divisor.
4. Bring down the dividend in the one's column and repeat it.
Step-by-step explanation:
Cos 200= -0.939692621. cos 115-sin200=-0.080598118 Sin 115=0.906307787
