Figure B is the answer!
The formula for the Pythagorean theorem is
A^2+B^2=C^2
In figure B the units are squared. Making it your answer.
-Seth
Answer:
k = 11/3
Step-by-step explanation:
If the line is tangent to the curve, then Δ = 0.
______________
Remembering:
Δ>0 two different points of intersection x'
x''
Δ=0 one point of intersection x' = x''
Δ<0 two different points of intersection in the complex plan x' and -x'
______________
As the line and the curve have one point of intersection, which is (x, y), we can make a equality between them:
2x + k = 3x² + 4
0 = 3x² - 2x + (4 - k)
Now we can use the Δ=0 (Δ= b² - 4ac)
Δ = 0 = (-2)² - 4.3.(4-k)
0 = 4 - 48 + 12k
12k = 44
k = 44/12 = 2 . 22 /3. 2.2 = 22/3.2 = 11/3
k = 11/3
Answer:
To solve for the volume of a sphere, you must first know the equation for the volume of a sphere.
V=43(π)(r3)
In this equation, r is equal to the radius. We can plug the given radius from the question into the equation for r.
V=43(π)(123)
Now we simply solve for V.
V=43(π)(1728)
V=(π)(2304)=2304π
Answer is 2304
Using the normal distribution, it is found that there was a 0.9579 = 95.79% probability of a month having a PCE between $575 and $790.
<h3>Normal Probability Distribution</h3>
The z-score of a measure X of a normally distributed variable with mean
and standard deviation
is given by:

- The z-score measures how many standard deviations the measure is above or below the mean.
- Looking at the z-score table, the p-value associated with this z-score is found, which is the percentile of X.
The mean and the standard deviation are given, respectively, by:
.
The probability of a month having a PCE between $575 and $790 is the <u>p-value of Z when X = 790 subtracted by the p-value of Z when X = 575</u>, hence:
X = 790:


Z = 1.8
Z = 1.8 has a p-value of 0.9641.
X = 575:


Z = -2.5
Z = -2.5 has a p-value of 0.0062.
0.9641 - 0.0062 = 0.9579.
0.9579 = 95.79% probability of a month having a PCE between $575 and $790.
More can be learned about the normal distribution at brainly.com/question/4079902
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