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Sever21 [200]
3 years ago
15

A line segment's measurement(s) include which of the following?

Mathematics
1 answer:
Effectus [21]3 years ago
7 0

Answer:

D. Length

Step-by-step explanation:

We measure the length of a line segment, and thus, the correct answer is given by option D.

The length of a line segment is the distance between it's endpoints, using the formula for the distance between two points given below.

Distance between two points:

Suppose that we have two points, (x_1,y_1) and (x_2,y_2). The distance between them is given by:

D = \sqrt{(x_2-x_1)^2+(y_2-y_1)^2}

You might be interested in
Which of the following is a solution to the equation x - 5/7 = -3/7
podryga [215]

Solve the equation:

          5              3
x  –  ——  =  –  ——
          7              7


           5
Add  ——  to both sides, so you get  x  isolated at the left-hand side:
           7

          5          5               3          5
x  –  ——  +  ——  =  –  ——  +  ——
          7           7              7           7

              3          5
x  =  –  ——  +  ——
              7           7


Now, add those fractions at the right-hand side of the equation:

          – 3 + 5
x  =  —————
               7

          2
x  =  ——     <———    this is the answer (first option:  2/7).
          7


I hope this helps. =)

8 0
3 years ago
Use the coordinate plane to help you identify the length of each leg then use the Pythagorean Theorem to find the length of CD
Nitella [24]

Answer:

CE= 9cm, DE= 5cm, CD= 10.2956cm

Step-by-step explanation:

Let E be the point of the other triangle.

Using Pythagoras' Theorem,

CD= square root symbol (CE^2 + DE^2)

= square root symbol (9^2+5^2)

= 10.2956cm (6 sf)

7 0
2 years ago
EXAMPLE 5 Find the maximum value of the function f(x, y, z) = x + 2y + 9z on the curve of intersection of the plane x − y + z =
geniusboy [140]

The Lagrangian,

L(x,y,z,\lambda,\mu)=x+2y+9z-\lambda(x-y+z-1)-\mu(x^2+y^2-1)

has critical points where its partial derivatives vanish:

L_x=1-\lambda-2\mu x=0

L_y=2+\lambda-2\mu y=0

L_z=9-\lambda=0

L_\lambda=x-y+z-1=0

L_\mu=x^2+y^2-1=0

L_z=0 tells us \lambda=9, so that

L_x=0\implies-8-2\mu x=0\implies x=-\dfrac4\mu

L_y=0\implies11-2\mu y=0\implies y=\dfrac{11}{2\mu}

Then with L_\mu=0, we get

x^2+y^2=\dfrac{16}{\mu^2}+\dfrac{121}{4\mu^2}=1\implies\mu=\pm\dfrac{\sqrt{185}}2

and L_\lambda=0 tells us

x-y+z=-\dfrac4\mu-\dfrac{11}{2\mu}+z=1\implies z=1+\dfrac{19}{2\mu}

Then there are two critical points, \left(\pm\frac8{\sqrt{185}},\mp\frac{11}{\sqrt{185}},1\pm\frac{19}{\sqrt{185}}\right). The critical point with the negative x-coordinates gives the maximum value, 9+\sqrt{185}.

8 0
3 years ago
Find the area of a triangle with a base of 12.5 cm and a height of 8 cm
dybincka [34]

Answer:

51.2 i think

Step-by-step explanation:

7 0
2 years ago
What is the circumference of this circle, in centimeters? Use 22/7 for Pi.
gtnhenbr [62]

Answer: 66cm

Step-by-step explanation:

Diameter (d) = 21 cm

c= πd = 22/7 x 21 = 22 x 3 = 66cm

3 0
2 years ago
Read 2 more answers
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