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tatiyna
3 years ago
10

Please help due today

Mathematics
1 answer:
otez555 [7]3 years ago
4 0
The answer is c
12.4 feet by 9.5 feet
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Find the value of x that will make A||B<br> 9x + 4<br> 5x + 20<br> x = [?]
mrs_skeptik [129]

9x + 4= 5x + 20 (alternate interior angles)

9x-5x =20-4

4x = 16

x= 16/4

x= 4

4 0
3 years ago
Read 2 more answers
Reduce fraction: a^3+a^2b/5a times 25/3b+3a
Margaret [11]

ANSWER

\frac{5a}{3}

EXPLANATION

The given fractions are:

\frac{{a}^{3}  +  {a}^{2} b}{5a}  \times  \frac{25}{3b + 3a}

We factor to obtain:

\frac{{a}^{2}(a  +   b)}{5a}  \times  \frac{25}{3(a + b)}

We cancel the common factors to get:

\frac{{a}(1)}{1}  \times  \frac{5}{3(1)}

We multiply the numerators and also multiply the denominators to get:

\frac{5a}{3}

Therefore the two fractions simplifies to \frac{5a}{3}

3 0
4 years ago
A tobacco company claims that the amount of nicotene in its cigarettes is a random variable with mean 2.2 and standard deviation
Aleksandr-060686 [28]

Answer:

0% probability that the sample mean would have been as high or higher than 3.1 if the company’s claims were true.

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal probability distribution

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Central limit theorem

The Central Limit Theorem estabilishes that, for a random variable X, with mean \mu and standard deviation \sigma, a large sample size can be approximated to a normal distribution with mean \mu and standard deviation s = \frac{\sigma}{\sqrt{n}}

In this problem, we have that:

\mu = 2.2, \sigma = 0.3, n = 100, s = \frac{0.3}{\sqrt{100}} = 0.03

What is the approximate probability that the sample mean would have been as high or higher than 3.1 if the company’s claims were true?

This is 1 subtracted by the pvalue of Z when X = 3.1. So

Z = \frac{X - \mu}{\sigma}

By the Central Limit Theorem

Z = \frac{X - \mu}{s}

Z = \frac{3.1 - 2.2}{0.03}

Z = 30

Z = 30 has a pvalue of 1.

1 - 1 = 0

0% probability that the sample mean would have been as high or higher than 3.1 if the company’s claims were true.

4 0
4 years ago
Mr. Cannon has a piece of land that is 3/7 of an acre. He wants to build 10 houses on his land. How much land does each house ge
sashaice [31]

Answer:

Step-by-step explanation:

3/7 divided by 10 houses= 0.042 acres per house

4 0
3 years ago
Pretty easy math equation I think but I forgot how to solve it look at picture
GrogVix [38]
X = 32 because 100 / 4 is 25, which would make the numerator for x 32
7 0
3 years ago
Read 2 more answers
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