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Rudiy27
3 years ago
13

Pretty please can you help with problem 7. (ONLY IF YOU KNOW)

Mathematics
2 answers:
Vika [28.1K]3 years ago
6 0
1 yard = 3 foot. 1 Foot = 12 inches.
She has 2 yards, 3 inches which = 6 foot 3 inches. 
She needs 5 foot 9 inches. 

She has more than enough, and to work out how much she has left - 
3 inches - 9 inches = -6 inches. -0.5 foot.
6 foot - 5 foot = 1 foot. 
1 foot - 0.5 foot. = 0.5 foot. She has 0.5 foot left over

Eddi Din [679]3 years ago
5 0
Yes she has enough inches
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A company wants to select 1 project from a set of 4 possible projects. Which of the following constraints ensures that only 1 wi
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Given:

A company wants to select 1 project from a set of 4 possible projects.

Consider the options are:

a. X_1+X_2+X_3+X_4=1

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c. X_1+X_2+X_3+X_4\geq 1

d. X_1+X_2+X_3+X_4\geq 0

To find:

The constraints that ensures only 1 will be selected.

Solution:

It is given that the company wants to select 1 project from a set of 4 possible projects. It means the sum of selected projects must be equal to 1.

X_1+X_2+X_3+X_4=1

Therefore, the correct option is (a).

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3 years ago
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This could happen in 3 ways.
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Which explanation best describes how to solve this problem?
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4 0
4 years ago
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Sholpan [36]

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Sally finds a coin with a radius of 1.5 centimeters and a thickness of 0.25 cm. It has a measured mass of 18.54 grams. How can S
mote1985 [20]

Answer:

Silver

Step-by-step explanation:

Find the volume of the coin

<u>Volume of a cylinder</u>

\textsf{V}=\sf \pi r^2 h \quad\textsf{(where r is the radius and h is the height)}

Given:

  • r = 1.5 cm
  • h = 0.25 cm

Substituting given values into the formula to find the volume:

\sf \implies V=\pi (1.5)^2(0.25)

\sf \implies V=0.5625 \pi \:cm^3

Find the density of the coin given it has a measured mass of 18.54 g

<u>Density formula</u>

\sf \rho=\dfrac{m}{V}

where:

  • \rho = density
  • m = mass
  • V = volume

Given:

  • m = 18.54 g
  • \sf V=0.5625 \pi \:cm^3

Substituting given values into the density formula:

\implies \sf \rho=\dfrac{18.54}{0.5625 \pi}

\implies \sf \rho=10.49149385\:g\:cm^{-3}

Given:

  • \textsf{Density of Lead}=\sf 11.3\:g\:cm^{-3}
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Therefore, as \sf \rho=10.49\:g\:cm^{-3} the coin is made from silver.

4 0
2 years ago
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