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2 years ago

Pretty please can you help with problem 7. (ONLY IF YOU KNOW)

Mathematics

2 answers:

Vika [28.1K]2 years ago

6 0

1 yard = 3 foot. 1 Foot = 12 inches.
She has 2 yards, 3 inches which = 6 foot 3 inches.
She needs 5 foot 9 inches.

She has more than enough, and to work out how much she has left -
3 inches - 9 inches = -6 inches. -0.5 foot.
6 foot - 5 foot = 1 foot.
1 foot - 0.5 foot. = 0.5 foot. She has 0.5 foot left over

Eddi Din [679]2 years ago

5 0

Yes she has enough inches

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The county fair charges $2.50 per ticket for the rides. Henry bought 15 tickets for the rides and spent a total of $55.50 at the

san4es73 [151]

Answer:

(A) $18

(B) $y=2.50x+18$ 

(C) Coefficient of x-term represents the cost for each ride ticket and constant term represents the cost of admission to the fair.

Step-by-step explanation:

(A)

The county fair charges $2.50 per ticket for the rides and Henry bought 15 tickets for the rides.

So, the total cost of the 15 tickets will be: $(\$2.50*15)= \$37.50$

He spent total $55.50 on ride tickets and fair admission.

So, the cost of admission to the fair will be: $(\$55.50-\$37.50)= \$18$

(B)

If $x$ represents the number of ride tickets and $y$ represents the total cost, then the cost for $x$ number of ride tickets is $\$2.50x$

So, the linear equation that can be used to determine the cost for anyone who pays for ride tickets and fair admission will be: $y= 2.50x+18$

(C)

In the above linear equation, coefficient of x-term is 2.50, which represents the cost for each ride ticket.

And the constant term is 18, which represents the cost of admission to the fair.

4 0

3 years ago

PLEASE HELP!!

erik [133]

$2.=c.\\\\2\sin4x\cos4x=2\sin(2\cdot4x)=2\sin8x\\\\Used:\\\sin2\alpha=2\sin\alpha\cos\alpha$

$1.=b.\\\\\csc x-\sin x=\dfrac{1}{\sin x}-\dfrac{\sin^2x}{\sin x}=\dfrac{1-\sin^2x}{\sin x}=\dfrac{\cos^2x}{\sin x}\\\\=\dfrac{\cos x\cos x}{\sin x}=\cos x\cdot\dfrac{\cos x}{\sin x}=\cos x\cot x\\\\Used:\\\csc x=\dfrac{1}{\sin x}\\\\\sin^2x+\cos^2x=1\to\cos^2x=1-\sin^2x\\\\\cot x=\dfrac{\cos x}{\sin x}$

$3.=a.\\\\\dfrac{\sin x-1}{\sin x+1}=\dfrac{\sin x-1}{\sin x+1}\cdot\dfrac{\sin x+1}{\sin x+1}=\dfrac{\sin^2x-1^2}{(\sin x+1)^2}=\dfrac{\sin^2x-1}{(\sin x+1)^2}\\\\=\dfrac{-(1-\sin^2x)}{(\sin x+1)^2}=\dfrac{-\cos^2x}{(\sin x+1)^2}\\\\Used:\\(a-b)(a+b)=a^2-b^2\\\\\sin^2x+\cos^2x=1\to \cos^2x=1-\sin^2x$

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3 years ago

Solve for x. 144° 18 degrees 30 degrees 48 degrees 120 degrees

disa [49]

Answer:

Step-by-step explanation:

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