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Rudiy27
2 years ago
13

Pretty please can you help with problem 7. (ONLY IF YOU KNOW)

Mathematics
2 answers:
Vika [28.1K]2 years ago
6 0
1 yard = 3 foot. 1 Foot = 12 inches.
She has 2 yards, 3 inches which = 6 foot 3 inches. 
She needs 5 foot 9 inches. 

She has more than enough, and to work out how much she has left - 
3 inches - 9 inches = -6 inches. -0.5 foot.
6 foot - 5 foot = 1 foot. 
1 foot - 0.5 foot. = 0.5 foot. She has 0.5 foot left over

Eddi Din [679]2 years ago
5 0
Yes she has enough inches
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The county fair charges $2.50 per ticket for the rides. Henry bought 15 tickets for the rides and spent a total of $55.50 at the
san4es73 [151]

Answer:

<em>(A)  $18</em>

<em>(B)   y=2.50x+18</em>

<em>(C)   Coefficient of x-term represents the cost for each ride ticket and constant term represents the cost of admission to the fair.</em>

Step-by-step explanation:

(A)

The county fair charges $2.50 per ticket for the rides and Henry bought 15 tickets for the rides.

So, the total cost of the 15 tickets will be:  (\$2.50*15)= \$37.50

He spent total $55.50 on ride tickets and fair admission.

So, the cost of admission to the fair will be:  (\$55.50-\$37.50)= \$18

(B)

If x represents the number of ride tickets and y represents the total cost, then the cost for x number of ride tickets is \$2.50x

So, the linear equation that can be used to determine the cost for anyone who pays for ride tickets and fair admission will be:   y= 2.50x+18

(C)

In the above linear equation, <u>coefficient of x-term is 2.50, which represents the cost for each ride ticket</u>.

And the <u>constant term is 18, which represents the cost of admission to the fair</u>.

4 0
3 years ago
PLEASE HELP!!
erik [133]
2.=c.\\\\2\sin4x\cos4x=2\sin(2\cdot4x)=2\sin8x\\\\Used:\\\sin2\alpha=2\sin\alpha\cos\alpha

1.=b.\\\\\csc x-\sin x=\dfrac{1}{\sin x}-\dfrac{\sin^2x}{\sin x}=\dfrac{1-\sin^2x}{\sin x}=\dfrac{\cos^2x}{\sin x}\\\\=\dfrac{\cos x\cos x}{\sin x}=\cos x\cdot\dfrac{\cos x}{\sin x}=\cos x\cot x\\\\Used:\\\csc x=\dfrac{1}{\sin x}\\\\\sin^2x+\cos^2x=1\to\cos^2x=1-\sin^2x\\\\\cot x=\dfrac{\cos x}{\sin x}

3.=a.\\\\\dfrac{\sin x-1}{\sin x+1}=\dfrac{\sin x-1}{\sin x+1}\cdot\dfrac{\sin x+1}{\sin x+1}=\dfrac{\sin^2x-1^2}{(\sin x+1)^2}=\dfrac{\sin^2x-1}{(\sin x+1)^2}\\\\=\dfrac{-(1-\sin^2x)}{(\sin x+1)^2}=\dfrac{-\cos^2x}{(\sin x+1)^2}\\\\Used:\\(a-b)(a+b)=a^2-b^2\\\\\sin^2x+\cos^2x=1\to \cos^2x=1-\sin^2x
8 0
3 years ago
Solve for x.<br> 144°<br> 18 degrees<br> 30 degrees<br> 48 degrees<br> 120 degrees
disa [49]

Answer:

<h2><u><em>x = 18 °</em></u></h2>

Step-by-step explanation:

you have a rotation angle of 360 °, take out the known values ​​(360 ° -90 ° -144 ° = 126), 144 ° is part of a flat angle of 180 °, from 180 ° remove 144 and you have 36 °, they are opposite angles therefore the same. therefore 360 ​​- 144 - 90 - 36 - 36 = 54.

54 is 3x, so x = 18 ° (54 : 3 = 18)

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2 years ago
How are rotations represented as function
Mumz [18]
Here is the answer from SparkNotes 

http://www.sparknotes.com/math/algebra2/operationsonfunctions/section3.rhtml
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3 years ago
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The answer is A.) 17.
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