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sasho [114]
3 years ago
12

Jessica's weight is 540 newtons. According to the Third Law, if the Earth pulls on Jessica with a force of 540 N, then Jessica p

ulls on the Earth with a force of 540 newtons that acts in the opposite direction. However, if Jessica stumbles while rollerblading, she will fall down to the ground. Explain why this happens.

Physics
2 answers:
Alja [10]3 years ago
8 0

This is because the earth is way heavier than Jessica hence has a greater force of gravity applied on Jessica that Jessica applies to earth. The distance between the Earth and Jessica is also very short hence the force of gravity on Jessica towards earth is greater. According to Newton's laws that states; if an unbalanced force acts on an object, it will change the object's state of motion (the object will accelerate). The earth cause Jesica to ‘accelerate’ towards the ‘core’ when she stumbles.

kvv77 [185]3 years ago
5 0

Answer:

Both forces are not acting on the same body, there is not balance

Explanation:

Jessica weights 540 N. If the Earth pulls on Jessica with a force of 540 N, so, Jessica pulls on the Earth with the same force of 540 N in the opposite direction.

When Jessica stumbles while rollerblading, she will fall to the ground. We need to explain this fact. We have two forces of the same magnitude 540 N and opposite direction, normally they should be in balance. However, this is not the case because each force acts on different bodies. 540 N are acting on Jessica down direction and 540 N are acting on the Earth up direction. In this sense, as both forces are not acting on the same body, there is not balance. Due to it, Jessica will fall to the ground, the net force on Jessica is 540 N down direction.

Finally, we can mention that both forces are not acting on the same body, there is not balance

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A 58.0 kg snow skier is on the top of 351 m high hill. After she has gone down a vertical distance of 142 m, what is her mechani
Nezavi [6.7K]

Answer:

Explanation:

Initially skier is at a height of 351 m . Her kinetic enery will be nil because she is at rest . Her potential energy will be calculated as follows

potential energy = mgh where m is mass , h is height and g is acceleration due to gravity

potential energy = 58 x 9.8 x 351

= 199508 .4 J

Total mehanical energy = potential energy + kinetic energy

= 199508.4 J

According to conservation of mechanical energy , at the height of 142 m also total mechanical energy will be same . At this height some potential energy will be converted into kinetic energy but total of potential and kinetic energy will be same.

8 0
3 years ago
How many arcseconds are in 1°? B) 360 A) 60 C) 3,600 D) 100 E) 10,000
jenyasd209 [6]

Answer:

C) 3,600

Explanation:

An arcsecond is equal to 1/3600 of a degree. Hence, the inverse will give the number of arcsecond in a degree. An arcsecond is one of the ways to measure angular measurement

1\ arcminute=\frac{1}{60}\ degree\\\Rightarrow 1\ degree=60\ arcminute

\\\Rightarrow 1\ degree=60\times 60\ arcsecond\\\Rightarrow 1\degree=3600\ arcsecond

5 0
3 years ago
I don’t get this question please help me
zvonat [6]

oof, that question is difficult! i would say its d because if you pull a slingshot farther than another one, it would have more potential energy.

6 0
3 years ago
Read 2 more answers
What is the name of the ratio of the voltage applied to a circuit and the current in a circuit
malfutka [58]
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4 0
4 years ago
A nonconducting sphere has radius R = 1.81 cm and uniformly distributed charge q = +2.08 fC. Take the electric potential at the
Sloan [31]

Answer:

a) V = -0.227 mV

b) V = -0.5169 mV

Explanation:

a)

Inside a sphere with a uniformly distributed charge density, electric field is radial and has a magnitude

E = (qr) / (4πε₀R³)

As we know that

V = -\int\limits^r_0 {E} \, dr

By solving above equation, we get

V = (-qr²) / (8πε₀R³)

When

R = 1.81 cm

r = 1.2 cm

q = +2.80 fC

ε₀ = 8.85 × 10⁻¹²

V = (-2.80 × 10⁻¹⁵ × (1.2 × 10⁻²)²) / (8 × 3.14 × 8.85 × 10⁻¹² × (1.81 × 10⁻²)³)

V = -2.27 × 10⁻⁴ V

V = -0.227 mV

b)

When

r = R

R = 1.81 cm

q = +2.80 fC

ε₀ = 8.85 × 10⁻¹²

V = (-qR²) / (8πε₀R³)

V = (-q) / (8πε₀R)

V = (-2.80 × 10⁻¹⁵) / (8 × 3.14 × 8.85 × 10⁻¹² × (1.81 × 10⁻²))

V = -5.169 × 10⁻⁴ V

V = -0.5169 mV

4 0
3 years ago
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