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yuradex [85]
3 years ago
9

Help please physics !!

Physics
1 answer:
malfutka [58]3 years ago
5 0

Answer:

Option A. 1 bar = 1 atm

Explanation:

Pressure has various units of measurement. Each unit of measurement can be converted to other units of measurement. For example:

1 atm = 1 bar

1 atm = 760 mmHg

1 atm = 760 torr

1 atm = 1×10⁵ N/m²

1 atm = 1×10⁵ Pa

With the above conversion scale we can convert from one unit to the other.

Considering the question given above, it is evident from the coversion scale illustrated above that only option A is correct.

Thus,

1 bar = 1 atm

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The absolute pressure below the surface of a freshwater lake is 3.51 x 10^5 Pa. At what depth does this pressure occur? Assume t
kupik [55]
The general formula for absolute pressure is:

P_{total}  = P_{atm} + (rgh)

Where: P_{total} = Absolute pressure
             P_{atm}  = atmospheric pressure
             r = density
             g = 9.8 \frac{m}{{s^2}}
             h = depth

We can use this formula to derive our formula for h:

P_{total} = P_{atm} + (rgh)      transpose atmospheric pressure
P_{total} - P_{atm} =  (rgh)     transpose r and g

P_{total} - P_{atm}
-------------------------      = h
         rg

Now let us input our given into our new formula:

3.52 x  10^{5} - 1.01 x 10^{5}
----------------------------------------              = h
1.00 x 10^{3} x 9.8 \frac{m}{ s^{2} }   

\frac{2.51 x {10^5}}{9.8 x {10^3} \frac{m}{s^2}} = h

25.61 m = h



6 0
3 years ago
The emf of a battery is equal to its terminal potential difference: A) under all conditions B) only when the battery is being ch
velikii [3]

Answer:

option (C)

Explanation:

EMF stand for electro motive force. the emf of a battery is the potential between the two electrodes when it is not use in the circuit.

The terminal potential difference is the potential difference between the electrodes of a cell when it is in use.

EMF is only when the current is very large in the battery.

4 0
3 years ago
Read 2 more answers
You wish to place a spacecraft in a circular orbit around the earth so that its orbital speed will be 4.00×103m/s. What is this
Levart [38]

Answer:

The radius of orbit=2.49\times 10^7 m

Explanation:

We are given that

Orbital speed=4.00\times 10^3m/s

We have to find the radius of orbit of spacecraft.

We know that

Gravitational constant=6.67\times 10^{-11}m^3/kgs^2

Mass of earth=5.972\times 10^{24} kg

Orbital speed=\sqrt{\frac{GM}{r}}

Where G= Gravitational constant

M=Mass of earth

r=Radius of orbit

Substitute the values in the formula

4\times 10^3=\sqrt{\frac{6.67\times 10^{-11}\times 5.972\times 10^{24}}{r}

Squaring on both sides

16\times 10^6=\frac{6.67\times 10^{-11}\times 5.972\times 10^{24}}{r}

r=\frac{6.67\times 10^{-11}\times 5.972\times 10^{24}}{16\times 10^6}

r=2.49\times 10^7 m

Hence, the radius of orbit=2.49\times 10^7 m

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