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sergey [27]
2 years ago
5

When two forces act in the same direction on an object, the net force is found by ....................the forces.

Physics
2 answers:
Anestetic [448]2 years ago
8 0

Answer:

Net force is found by sum of the forces.

Anna [14]2 years ago
7 0

Answer:

The correct answer is When two forces act in the same direction on an object, the net force is found by the sum of the forces.

Hope this helps you!!

Please mark me Brainleast!!

<h2><em>Thankyou for joining Brainly communicty!!!</em></h2>

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10. The electron dot diagram for the element Ne would have ​
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Answer:

2,8

Explanation:

The first electron shell would have 2 electrons, the second shell would have 8 electrons. This is because Neon has a relative charge of 10.

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Pangaea one major super-continent.
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What type of kinetic energy does flowing water have?
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none it's Hydroelectric energy

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. Using your knowledge of circular (centripetal) motion, derive an equation for the radius r of the circular path that electrons
Ronch [10]

Answer:

Explanation:

Magnetic field creates a force perpendicular to a moving charge in its field which is equal to Bev where B is magnetic field , e is amount of charge on the moving charge and v is the velocity of charge particle .

This force provides centripetal force for creation of circular motion. If r be the radius of the circular path

Bev = mv² / r

r = mv / Be

2 ) If an electron is accelerated by an electric field created by potential difference V then electric field

= V / d where d is distance between two points having potential difference v .

force on charged particle

electric field x charge

= V /d x e

work done by field

= force x distance

= V /d x e x d

V e

This is equal to kinetic energy created

V e = 1/2 mv²

= 1/2 m (r²B²e² / m² )

V = r²B²e/ 2 m

e / m = 2 V/ r²B²

3 )

B = \frac{\mu\times I\times R^2}{2(R^2+Z^2)^\frac{3}{2} }

In Helmholtz coils , distance between coil is equal to R so Z = R/2

B = \frac{\mu\times I\times R^2}{2(R^2+\frac{R^2}{4} )^\frac{3}{2} }

For N turns of coil and total field due to two coils

B = \frac{\mu\times I\times N}{R\times(\frac{5}{4})^\frac{3}{2}  }

= \frac{\mu\times I\times N}{R}\times (\frac{4}{5})^\frac{3}{2}

= 9.0 x 10^-7 NI/R

8 0
4 years ago
A 2.0 kg mass attached to an ideal spring oscillates horizontally with an amplitude of 0.15 m. The spring constant is 85N/M
dimulka [17.4K]

Answer:

I think the answer is electric potential.

4 0
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