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3 years ago

Guys i need ur help fast please

Mathematics

1 answer:

Maslowich3 years ago

6 0

Answer:

a) -3

b) 5

c) 7

d) 4

Step-by-step explanation:

We have the function $p(x)=5x^3-3x^2+2x^5+7$

a) We need to find the coefficient of $x^2$ .

This means that we need to find out what number is alongside the $x^2$ in this equation. From the function, we can find that it is -3

b) Now we need to find the degree of $p(x)$ . Recall that the degree refers to the highest power of x that is present. As $x^5$ is the largest power, our degree would be 5.

c) The constant term refers to the number within the function that does not have any x's with it. In this function, that number would be 7.

d) Now we need to find the number of terms. For this one, we just need to count how many terms are separated by + or - signs. There are 4 in this function.

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Step-by-step explanation:

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3 years ago

Which is the simplified form of the expression ((2 Superscript negative 2 Baseline) (3 Superscript 4 Baseline)) Superscript nega

AlekseyPX

Answer:

The option "StartFraction 1 Over 3 Superscript 8" is correct

That is $\frac{1}{3^8}$ is correct answer

Therefore $[(2^{-2})(3^4)]^{-3}\times [(2^{-3})(3^2)]^2=\frac{1}{3^8}$

Step-by-step explanation:

Given expression is ((2 Superscript negative 2 Baseline) (3 Superscript 4 Baseline)) Superscript negative 3 Baseline times ((2 Superscript negative 3 Baseline) (3 squared)) squared

The given expression can be written as

$[(2^{-2})(3^4)]^{-3}\times [(2^{-3})(3^2)]^2$

To find the simplified form of the given expression :

$[(2^{-2})(3^4)]^{-3}\times [(2^{-3})(3^2)]^2$

$=(2^{-2})^{-3}(3^4)^{-3}\times (2^{-3})^2(3^2)^2$ ( using the property $(ab)^m=a^m.b^m$ )

$=(2^6)(3^{-12})\times (2^{-6})(3^4)$ ( using the property $(a^m)^n=a^{mn}$

$=(2^6)(2^{-6})(3^{-12})(3^4)$ ( combining the like powers )

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Therefore $[(2^{-2})(3^4)]^{-3}\times [(2^{-3})(3^2)]^2=\frac{1}{3^8}$

Therefore option "StartFraction 1 Over 3 Superscript 8" is correct

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3 years ago

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andrew11 [14]

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Step by step explanation
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2 years ago

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ivann1987 [24]

Answer:

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3 years ago

Guys i need ur help fast please ​

Guys i need ur help fast please