Ask question

Ask question

All categories

3 years ago

5

The lines graphed below are parallel. The slope of the red line is -4/3. What is the slope of the green line?

1 answer:

Anna35 [415]3 years ago

6 0

-4/3

Parallel lines have the same slope.

You might be interested in

Write an equation of each line in standard form with integer coefficients.<br> 4. y = 2.4x + 1.8

Nadusha1986 [10]

Answer:

<h2>12x - 20y = -9</h2>

Step-by-step explanation:

The standard form of an equation of a line:

$Ax+By=C$

We have

$4y=2.4x+1.8$

Convert

$4y=2.4x+1.8$ <em>multiply both sides by 10</em>

$40y=24x+18$ <em>subtract 24x from both sides</em>

$-24x+40y=18$ <em>change the signs</em>

$24x-40y=-18$ <em>divide both sides by 2</em>

$12x-20y=-9$

3 0

3 years ago

Which table represents a linear function?

horsena [70]

Answer:

Step-by-step explanation:

Do you have any answer choices for this or I can’t answer it

6 0

3 years ago

The air quality was tested in many office buildings in two cities. The results of the testing is shown in this box plots.

frozen [14]

A C & D If The Air Quality Was Tested .

3 0

4 years ago

Read 2 more answers

Two trains 150 miles apart are traveling toward each other along the same track. The first train goes 60 miles per hour; the sec

Nataly_w [17]

Answer:

120 miles

Step-by-step explanation:

Distance = 150 miles

train 1 = 60 mph

train 2 = 90 mph

directions of trains = towards each other

Time to meet = 150/(60+90) = 150 miles / 150 mph = 1 hour

Speed of fly = 120 mph

Since fly has been flying for one hour, it travelled 120 miles.

3 0

3 years ago

Determine determine whether the following geometric series converges or diverges. if the series converges find its sum.

Lilit [14]

For starters,

$\dfrac{3^k}{4^{k+2}}=\dfrac{3^k}{4^24^k}=\dfrac1{16}\left(\dfrac34\right)^k$

Consider the $n$ th partial sum, denoted by $S_n$ :

$S_n=\dfrac1{16}\left(\dfrac34\right)+\dfrac1{16}\left(\dfrac34\right)^2+\dfrac1{16}\left(\dfrac34\right)^3+\cdots+\dfrac1{16}\left(\dfrac34\right)^n$

Multiply both sides by $\frac34$ :

$\dfrac34S_n=\dfrac1{16}\left(\dfrac34\right)^2+\dfrac1{16}\left(\dfrac34\right)^3+\dfrac1{16}\left(\dfrac34\right)^4+\cdots+\dfrac1{16}\left(\dfrac34\right)^{n+1}$

Subtract $S_n$ from this:

$\dfrac34S_n-S_n=\dfrac1{16}\left(\dfrac34\right)^{n+1}-\dfrac1{16}\left(\dfrac34\right)$

Solve for $S_n$ :

$-\dfrac14S_n=\dfrac3{64}\left(\left(\dfrac34\right)^n-1\right)$

$S_n=\dfrac3{16}\left(1-\left(\dfrac34\right)^n\right)$

Now as $n\to\infty$ , the exponential term will converge to 0, since $r^n\to0$ if $0$ . This leaves us with

$\displaystyle\lim_{n\to\infty}S_n=\lim_{n\to\infty}\sum_{k=1}^n\frac{3^k}{4^{k+2}}=\sum_{k=1}^\infty\frac{3^k}{4^{k+2}}=\frac3{16}$

8 0

3 years ago

Read 2 more answers