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-BARSIC- [3]
2 years ago
8

6x+a=5(x+t) make x the subject of the formula

Mathematics
1 answer:
Maslowich2 years ago
6 0

Answer:

X= -a/5 - 6/5c +t

so 6c+a=5(x+t)

1. distribute the 5 to x and t

6c+a=5x+5t

then you want to get x alone - subtract/add on both sides.

6c+a=5x+5t

-a -a

6c=5x+5t-a

-6c -6c

-5x -5x

-5x= (-a) - 6c + 5t

then divide each side by negative 5 to get X.

X= -a/5 - 6/5c +t

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mojhsa [17]

Answer: y = -1,2x + 3.4

Step-by-step explanation:

y = ax + b

(2,1)      => 1    = 2a + b (1)

(17,-17) => -17 =17a + b (2)

Using caculator Mode => 5 =>1

We get : a=- 1.2 , b = 3.4

=> y = -1.2x + 3.4

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2 years ago
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Step-by-step explanation:

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2 years ago
Which expression is equal to 5^4 ⋅ 5^8?
alex41 [277]

It should be A. You would keep the 5, and the exponent should be 4+8, which is 12.

3 0
3 years ago
Read 2 more answers
The relation ((6, 8), (7, 10), (7, 12), (8, 16),
Brilliant_brown [7]

Answer:

x = 7 is repeated twice.

Hence, there is NO MORE unique input. We can not have repeated inputs.

Thus, the relation is NOT a function.

Step-by-step explanation:

Given the relation

  • {(6, 8), (7, 10), (7, 12), (8, 16), (10, 16)}

We know that a relation is a function that has only one output for any unique input.

As the inputs or x-values of the relations are:

at x = 6, y = 8

at x = 7, y = 10

at x = 7, y = 12

at x = 8, y = 16

at x = 10, y = 16

If we closely observe, we can check that there is a repetition of x values.

i.e. x = 7 is repeated twice.

Hence, there is NO MORE unique input. We can not have repeated inputs.

Thus, the relation is NOT a function.

8 0
3 years ago
Carmen and Matt are conducting different chemistry experiments in school. In both experiments, each student starts with an initi
dangina [55]

This question is incomplete and it lacks an attached graph. Find attached to this answer, the appropriate graph.

Complete Question

Carmen and Matt are conducting different chemistry experiments in school. In both experiments, each student starts with an initial amount of water in a flask. They combine two chemicals which react to produce more water. Carmen's experiment starts with 30 milliliters of water in a flask, and the water increases in volume by 8.5 milliliters per second. Matt's experiment starts with 10 milliliters of water and increases in volume by 28% each second. The graph represents the volume of water in the two flasks in relation to time. Which two conclusions can be made if f represents the volume of water in Carmen's flask and g represents the volume of water in Matt's flask? a) The volume of water in Carmen's flask is increasing at a slower rate than the volume of water in Matt's flask over the interval [0, 2].

b) The volume of water in Carmen's flask is increasing at a faster rate than the volume of water in Matt's flask over the interval [6, 8].

c) The volume of water in Carmen's flask will always be greater than the volume of water in Matt's flask.

d) The volume of water in Matt's flask will eventually be greater than the volume of water in Carmen's flask.

e) The volume of water in Carmen's flask is increasing at a slower rate than the volume of water in Matt's flask over the interval [4, 6].

Answer:

c) The volume of water in Carmen's flask will always be greater than the volume of water in Matt's flask.

e) The volume of water in Carmen's flask is increasing at a slower rate than the volume of water in Matt's flask over the interval [4, 6].

Step-by-step explanation:

Looking at the graph, the average rate of change is given as [0,2], [4,6], and [6,8].

From the graph and question, we can tell that Matt's experiment starts with 10 milliliters of water and increases in volume by 28% each second

Which would gives us:

28% of 10 milliliter of water = 2.8 millimeters per second.

For Carmen , his experiment starts with 30 milliliters of water in a flask, and the water increases in volume by 8.5 milliliters per second,

Because, Carmen starts with 30 milliliters of water in his flask, the volume of water in Carmen's flask will always be greater than the volume of water in Matt's flask.

Secondly, comparing the quantity as which the volume of the flask increases per second, at the interval of [4, 6], the volume of water in Carmen's flask is increasing at a slower rate than the volume of water in Matt's flask over the interval

7 0
2 years ago
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