Answer:
see explanation
Step-by-step explanation:
Given
(x - 3) × (x + 4) = 0, that is
(x - 3)(x + 4) = 0
The zero product indicates that (x - 3) = 0 or (x + 4) = 0
x - 3 = 0 ⇒ x = 3
x + 4 = 0 ⇒ x = - 4
Thus if x = 3, then
(3 - 3)(x + 4) = 0 × (x + 4) = 0
Similarly if x = - 4 the output is zero
3x^(2)+4x-3x-5-2=0
3x^(2)+x-7=0
Discriminat= b^(2)-4ac= 1^(2)-4(3)(-7)= 1-12(-7)=1+84=85
The discrimination is bigger than 0 (delta>0) therefore there are 2 real solutions
Answer:
C) Octagon
Step-by-step explanation:
Answer:
P = 9 is the max value
Step-by-step explanation:
Sketch
2x + 4y = 10
with x- intercept = (5, 0) and y- intercept (0, 2.5)
x + 9y = 12
with x- intercept = (12, 0) and y- intercept = (0,
)
Solve
2x + 4y = 10 and x + 9y = 12 to find the point of intersection at (3, 1)
The region corresponding to the solution of the system of constraints
Has vertices at (0,
), (0, 0) , (5, 0) and (3, 1)
Now evaluate the objective function at each vertex.
(0, 0) can be excluded as it will not give a maximum
(5, 0) → P = 5 + 0 = 5
(0,
) → 0 + 8 = 8
(3, 1) → 3 + 6(1) = 3 + 6 = 9 ← maximum value
Thus the maximum value is 9 when x = 3 and y = 1
1+1 is 2
I hope that helped