Letting n approach infinity results in the undefined "infinity over infinity."
Differentiate numerator and denominator separately, obtaining
1/n
(limit as n approaches infinity of) ------------- = 0. Series is convergent.
2n
Rocco would have to run diagonally 27 times
An example for #1 would be that: 15 is divisible by 3, but not 9. every third multiple of 3, (9, 18, 27,...) is divisible by 9 because 9 is three times the size of 3.
For part two the first number that I thought of is 23.
Answer:
its12
Step-by-step explanation:
Answer:
i think it is 1% sry if wrong
Step-by-step explanation: