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Alexandra [31]
4 years ago
13

An auditorium is in the shape of an equilateral triangle. the stage extends from one vertex of the triancle to the midsegment, a

nd the seating area extends from the midsegment to the resr wall. the rear wall measures 112 feet. what is the perimeter of the seating area.

Mathematics
1 answer:
postnew [5]4 years ago
4 0

Answer:

280 ft

Step-by-step explanation:

An auditorium is in the shape of an equilateral triangle with side length as 112 ft.

The stage extends from one vertex of the triangle to the mid-segment and the seating area extends from the mid-segment to the rear wall.

*The situation is represented in the attachment.

According to the midpoint theorem, the segment joining two sides of a triangle at the midpoints of those sides is parallel to the third side and is half the length of the third side.

Hence, the length of the mid-segment in this case is,

\dfrac{1}{2}\times 112=56\ ft

Therefore, the perimeter of the seating area is,

=112+56+56+56=280\ ft

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The base of a triangle exceeds the height by 9 centimeters. If the area is 56 square centimeters, find the length of the base an
shepuryov [24]

Answer:

The height of the triangle is 7cm and the base is 16cm

Step-by-step explanation:

First of all we have to know the formula to calculate area of ​​a triangle

a = area = 56

b = base

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a = (b * h)/2

we replace the known values and we make 2 equations

56cm² = (b * h)/2

b = h + 9cm

we replace b by (h + 9cm) in the first equation

56cm² = (h + 9cm * h)/2

56cm² * 2 = h² + 9h

0 = h² + 9h - 112cm²

we use bhaskara formula:

(-b (±) √ (b² - 4ac) ) / 2a

we replace with the known values

h = (-9 (±) √ (9² - 4*1*(-112) ) ) / 2*1

h = (-9 (±) √ (81 + 448) ) ) / 2

h = (-9 (±) √529) /2

h = (-9 (±) 23)/2

h1 = (-9 + 23) / 2

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h2 = -16

The height of the triangle is 7cm and the base is 16cm

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3 years ago
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