Type of NR: alpha 235 U —> + 231 Th 92 ___ 90
1 answer:
Type of NR: alpha 235 U —> + 231 Th 92 ___ 90
Answer: ²³⁵92U → ⁴2He(2p,2n) + ²³¹90Th.
Answer: ²³⁵92U → Helium nucleus + ²³¹90Th.
Explanation : This is typical Alpha decay, as an alpha is a Helium Nucleus. The Alpha decay of Uranium-235 changes both the mass number and the atomic number of the element from 235 to 231 and from 92 to 90. The mass number decreases by 4, and the atomic number decreases by 2. This gives rise to the formation of a new element - Thorium-231.
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The reaction described above is the formation of an acetal. The initial starting material has a central carbonyl and two terminal alcohol functional groups. In the presence of acid, the carbonyl will become protonated, making the carbon of the carbonyl susceptible to nucleophilic attack from one of the alcohols. The alcohol substitutes onto the carbon of the carbonyl to provide us with the intermediate shown.
The intermediate will continue to react in the presence of acid and the -OH that was once the carbonyl will become protonated, turning it into a good leaving group. The protonated alcohol leaves and is substituted by the other terminal alcohol to give the final acetal product. The end result of the overall reaction is the loss of water from the original molecule to give the spiroacetal shown in the image provided.
The intermediate will continue to react in the presence of acid and the -OH that was once the carbonyl will become protonated, turning it into a good leaving group. The protonated alcohol leaves and is substituted by the other terminal alcohol to give the final acetal product. The end result of the overall reaction is the loss of water from the original molecule to give the spiroacetal shown in the image provided.
We have that the the molarity of methanol in the solution is mathematically given as
Morality=7.91mol/l
<h3>Chemical Reaction</h3>Question Parameters:
An <u>aqueous </u><em>solution </em>of methanol (MM = 32.04 g/mol)
A molality of 8.83 m and a density of 1.15 g/mL.
Generally the equation for the is mathematically given as
where
Mass of solution=(100+282.2)
Mass of solution=1289.9
Volume=1289.9/1.15
Volume=1.115L
Therefore
Morality=8.83/1.115
Morality=7.91mol/l
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