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Readme [11.4K]
3 years ago
5

The Na /K pump generates a membrane potential across the plasma membrane (PM) of the cell by transporting Na and K across the PM

. The action of this pump results in the cell having a slightly ____________ charge inside the cell compared to the extracellular space.
Chemistry
1 answer:
cestrela7 [59]3 years ago
3 0

Answer:

NEGATIVE CHARGE can best fill in the gap

Explanation:

The Na /K pump functions to maintain resting potential so that the cells will be kept in a state of a low concentration of sodium ions and high levels of potassium ions within the cell.

The processes of Na - K pump illustrates active transport since it moves Na+ and K+ ions against their concentration gradient. The energy required is supplied by the breakdown of ATP (adenosine triphosphate) to ADP (adenosine diphosphate). In nerve cells the pump is used to generate gradients of both sodium and potassium ions.

How does the sodium-potassium pump contribute to the net negative charge of the interior of the cell?

The sodium-potassium pump forces out three (positive) Na+ ions for every two (positive) K+ ions it pumps in, thus the cell loses a positive charge at every cycle of the pump.

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A doctor orders a blood sample from a child to test for traces of lead in the blood. Which of the following concentration
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Answer:percentage by mass

Explanation:

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3 years ago
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What mass of methane (in g) must be burned in order to liberate 12567 kJ of heat?
Ierofanga [76]

Answer:

Mass of methane required in gram = 226.35 gram (Approx.)

Explanation:

Given:

Heat energy used = 12,567 kJ

Missing data;

Δcombustion = 891  kJ/mol

Find:

Mass of methane required in gram

Computation:

Number of mol methane burned = Heat energy used / Δcombustion

Number of mol methane burned = 12,571 / 891

Number of mol methane burned = 14.1088 mol

1 mol of methane in gram = 16.043 grams

So,

Mass of methane required in gram = Number of mol methane burned x 1 mol of methane in gram

Mass of methane required in gram = 14.1088 x 16.043

Mass of methane required in gram = 226.3474

Mass of methane required in gram = 226.35 gram (Approx.)

4 0
3 years ago
The enthalpy of combustion of octane is -5470 kJ/mol. Octane (formulae C8H18) was used to heat some water in a copper can. The a
Virty [35]

Answer: 0.0009 moles of octane were used up.

Explanation:

To calculate the moles :

\text{Moles of solute}=\frac{\text{given mass}}{\text{Molar Mass}}

Given mass of octane = 0.1 g

Molar mass of octane = 11.23 g/mol  

Putting in the values we get:

\text{Moles of octane}=\frac{0.1g}{114.23g/mol}=0.0009moles

Thus 0.0009 moles of octane were used up.

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4 years ago
In need of a friend, boys 13-14 comment or answer if your in!
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Answer:

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Explanation:

u can join servers and everything, when i had the app i met over 200 people. so i recommend.

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3 years ago
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if 20.2g of NO and 13.8g of O2 are used to form NO2, how many moles of excess reactant will be left over
ruslelena [56]

Answer:

0.095 moles of O₂ are left over.

Explanation:

First of all, state the balanced reaction:

2NO + O₂ → 2NO₂

We determine moles of each reactant:

20.2 g . 1mol / 30g =  0.673 moles of NO

13.8g . 1mol / 32g = 0.431 moles of oxygen

Oxygen is the excess reactant. Let's see.

For 2 moles of NO I need 1 mol of O₂

Then, for 0.673 moles of NO I may use (0.673 .1) /2 = 0.336 moles

I have 0.431 moles of O₂ and I only need 0.336 mol. According to reaction, stoichiometry is 2:1.

In conclussion, the moles of excess reactant that will be left over:

0.431 - 0.336 = 0.095 moles

6 0
3 years ago
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