2 years ago

When you have added as much solute as can dissolve in solvent the solution is called

Chemistry

1 answer:

Paha777 [63]2 years ago

7 0

Solubility limit. that's the answer

You might be interested in

Each year, the science club puts on a science show for the students in the elementary school. Luis is planning demonstrations to

Harlamova29_29 [7]

Mallebility, I got it right on the unit test.

6 0

3 years ago

Read 2 more answers

Okay help please will give brainlist

pashok25 [27]

Answer:

Explanation:

hope that helped you

3 0

3 years ago

At what temperatures is a reaction that has a positive change in entropy

Setler [38]

Answer:

the answer is A

I made a chart for AP chem if you want to refer to it.

3 0

3 years ago

Using the chemical equation below, how many moles of Al2O3 produce when 105 grams of Al are reacted? 2Al+Fe2O3 —> Al2O3+2Fe

topjm [15]

Answer:

1.94

Explanation:

moles = mass/Mr so you have 3.889 moles of aluminium, but because the ratio in the equation is 2:1 you need to halve it.

4 0

3 years ago

Complete combustion of 5.90 g of a hydrocarbon produced 19.2 g of CO2 and 5.89 g of H2O. What is the empirical formula for the h

scZoUnD [109]

$44g \ CO_{2} \ \ \ \rightarrow \ \ 12g \ C\\
19,2g \ CO_{2} \rightarrow \ \ \ x\\\\
x=\frac{19,2g*12g}{44g}\approx5,24g \ \ \ \Rightarrow \ \ n=\frac{5,24g}{12\frac{g}{mol}}\approx0,44mol\\\\\\
18g \ H_{2}O \ \ \ \rightarrow \ \ \ 2g \ H\\
5,89g \ H_{2}O \ \rightarrow \ \ y\\\\
y=\frac{5,89g*2g}{18g}\approx0,65g \ \ \ \ \Rightarrow \ \ n=\frac{0,65g}{1\frac{g}{mol}}=0,65mol\\\\\\
n_{C}:n_{H}=0,44:0,65\approx1:1\\\\
CH$

4 0

3 years ago