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kolbaska11 [484]
3 years ago
5

This figure (Figure 1)shows a container that is sealed at the top

Chemistry
1 answer:
guajiro [1.7K]3 years ago
7 0
I'm pretty sure the answer is 0.833 atm.

Hope I helped! <3

-cara
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Four balloons, each with a mass of 10.0 g, are inflated to a volume of 20.0 L, each with a different gas: helium, neon, carbon m
weeeeeb [17]
On temperature 25°C (298,15K) and pressure of 1 atm each gas has same amount of substance:
n(gas) = p·V ÷ R·T = 1 atm · 20L ÷ <span>0,082 L</span>·<span>atm/K</span>·<span>mol </span>· 298,15 K
n(gas) = 0,82 mol.
1) m(He) = 0,82 mol · 4 g/mol = 3,28 g.
d(He) = 10 g + 3,28 g ÷ 20 L = 0,664 g/L.
2) m(Ne) = 0,82 mol · 20,17 g/mol = 16,53 g.
d(Ne) = 26,53 g ÷ 20 L = 1,27 g/L.
3) m(CO) = 0,82 mol ·28 g/mol = 22,96 g.
d(CO) = 32,96 g ÷ 20L = 1,648 g/L.
4) m(NO) = 0,82 mol ·30 g/mol = 24,6 g.
d(NO) = 34,6 g ÷ 20 L = 1,73 g/L.
6 0
3 years ago
Read 2 more answers
Write the action of monohydroxy benzene with aqueous bromine​
Romashka-Z-Leto [24]

The reaction yields the product compound 2,4,5-tribromophenol.

<h3>Bromination of monohydroxy benzene</h3>

Bromination is an organic reaction in which aqueous bromine is made to react with another compound so as to introduce bromine into the molecule.

When we carry out the bromination of monohydroxy benzene, we obtain the compound 2,4,5-tribromophenol.

Learn more about benzene: brainly.com/question/14525517

5 0
2 years ago
How much work is required to lift a 0.500 kg block 18.5 m?
kipiarov [429]

Answer:

Work = 90.65 j

Explanation:

Given data:

Mass = 0.500 Kg

Distance = 18.5 m

Work done = ?

Solution:

Work = force . distance

Force = mg

Work = mg.distance

Work = mgh

Work = 0.500 Kg × 9.8 m/s²× 18.5 m

Work = 90.65 Kg .m²/s²

Kg .m²/s² = j

Work = 90.65 j

3 0
3 years ago
Which of the following measurements has three significant figures?
Free_Kalibri [48]

The correct answer is <u>C: 0.510 m</u>

<u></u>

N I C E - D A Y!

8 0
2 years ago
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Who created the planetary model of the atom?
shtirl [24]
The answer is Rutherford.
4 0
2 years ago
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