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LuckyWell [14K]
4 years ago
5

A maple tree could be studied in many fields of science. What aspect of a maple tree might be studied in chemistry

Chemistry
1 answer:
Elden [556K]4 years ago
4 0

Answer:

botany because a maple tree is a plant

Explanation:

You might be interested in
A.Which facilities contribute the most to recycling and the least to recycling based on the pie chart graphic?
nirvana33 [79]

Answer:

a) To determine the facilities that contribute the most to recycling check the pie chart and select the facility with the largest portion while to determine the facilities that contribute the least to recycling check the pie chart and select the facility with the smallest portion

b) Energy is saved because the products which are recycled usually require less energy to turn them into usable materials

c) It saves energy through recycling. It helps sustains the environment. It decrease the emission of green house gases

Explanation:

The question is not complete

a) Pie chart is the graphical representation of information in which the information is represented in a circle. The circle is divided into segments and the portion with the largest segment has the highest percentage.

To determine the facilities that contribute the most to recycling check the pie chart and select the facility with the largest portion while to determine the facilities that contribute the least to recycling check the pie chart and select the facility with the smallest portion

b) Extraction and processing of raw resources to make end products requires a lot of energy.  With recycling energy is saved because the products which are recycled usually require less energy to turn them into usable materials

c) It saves energy through recycling. It helps sustains the environment. It decrease the emission of green house gases.

6 0
3 years ago
If 20 ml of a 0.5 M sodium hydroxide solution is necessary to neutralize 40 ml of an acid solution, what is the concentration of
leonid [27]

Answer: The concentration of the acid is 0.01 moles acid/0.040 L = 0.25 moles/L = 0.25 M

Explanation:

8 0
3 years ago
A chemist adds of a zinc nitrate solution to a reaction flask. Calculate the mass in kilograms of zinc nitrate the chemist has a
Ray Of Light [21]

Answer:

5.3 × 10⁻³ kg

Explanation:

There is some info missing. I think this is the original question.

<em>A chemist adds 135.0 mL of a 0.21 M zinc nitrate (Zn(NO₃)₂) solution to a reaction flask. Calculate the mass in kilograms of zinc nitrate the chemist has added to the flask. Be sure your answer has the correct number of significant digits.</em>

<em />

We have 135.0 mL of a 0.21 M zinc nitrate (Zn(NO₃)₂) solution. The moles of zinc nitrate are:

0.1350 L × 0.21 mol/L = 2.8 × 10⁻² mol

The molar mass of zinc nitrate is 189.36 g/mol. The mass corresponding to 2.8 × 10⁻² moles is:

2.8 × 10⁻² mol × 189.36 g/mol = 5.3 g

1 kilogram is equal to 1000 grams. Then,

5.3 g × (1 kg/1000 g) = 5.3 × 10⁻³ kg

8 0
3 years ago
If there are 1.55 x 1024 molecules of hydrogen peroxide (H2O2), what is the mass of the<br>sample? ​
bezimeni [28]

Answer:

87.54 g of H₂O₂

Explanation:

From the question given above, the following data were obtained:

Number of molecules = 1.55×10²⁴ molecules

Mass of H₂O₂ =.?

From Avogadro's hypothesis,

6.02×10²³ molecules = 1 mole of H₂O₂

Next, we shall determine the mass of 1 mole of H₂O₂. This can be obtained as follow:

1 mole of H₂O₂ = (2×1) + (2×16)

= 2 + 32

= 34 g

Thus,

6.02×10²³ molecules = 34 g of H₂O₂

Finally, we shall determine mass of H₂O₂ that contains 1.55×10²⁴ molecules. This can be obtained as follow:

6.02×10²³ molecules = 34 g of H₂O₂

Therefore,

1.55×10²⁴ molecules

= (1.55×10²⁴ × 34)/6.02×10²³

1.55×10²⁴ molecules = 87.54 g of H₂O₂

Thus, 87.54 g of H₂O₂ contains 1.55×10²⁴ molecules.

8 0
3 years ago
A sample initially contains 8.0 moles of a radioactive isotope. How much of the sample remains after four half-lives? Express yo
Tju [1.3M]

Answer:

0.50 mol

Explanation:

The half-life is <em>the time required for the amount of a radioactive isotope to decay to half that amount</em>.

Initially, there are 8.0 moles.

  • After 1 half-life, there remain 1/2 × 8.0 mol = 4.0 mol.
  • After 2 half-lives, there remain 1/2 × 4.0 mol = 2.0 mol.
  • After 3 half-lives, there remain 1/2 × 2.0 mol = 1.0 mol.
  • After 4 half-lives, there remain 1/2 × 1.0 mol = 0.50 mol.

6 0
3 years ago
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