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Degger [83]
3 years ago
6

What is the equation for the line

Mathematics
1 answer:
Pavel [41]3 years ago
6 0
The model equation for any line is
y = mx + b,
where m is slope and b is y-intercept (where the line intersects the y-axis).

The slope is change in y over change in x. You can find the slope by picking two points. The numerator will be the difference in y-coordinates, and the denominator will be the difference in x-coordinates.
As an equation, this is
slope = \frac{y2-y1}{x2-x1},
where the two points are (x1, y1) and (x2, y2).

Let's pick two points to find the slope: (0, 5) and (3, -7).
The slope is 
\frac{-7-5}{3-0} = \frac{-12}{3} = -4

Now that we have the slope m = -4, we need to find the y-intercept b. The line crosses the y-axis at 5, so b = 5.

The equation is y = -4x + 5
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2 years ago
ZN
solmaris [256]

Given tangent, ZN, to the circle and the arc \widehat{ZMB} = 280°, we have that

the angle formed by the chord BZ and the tangent ZN, ∠BZN is 50°

<h3>Which method can be used to find ∠BZN?</h3>

The given parameters are;

A tangent to the circle O = ZN

m \widehat{ZMB}} = \mathbf{280^{\circ}}

Required:

Angle ∠BZN

Solution;

Please find attached the drawing of the circle and tangent

From the drawing, we have;

∠BOZ = 360° - 280° = 80°

ΔBOZ is an isosceles triangle, which gives;

∠BZO = ∠ZBO

\angle BZO = \dfrac{(180^{\circ}- 80^{\circ}) }{2} = \mathbf{50^{\circ}}

∠OZN = 90° (by definition of a tangent)

∠OZN = ∠BZO + ∠BZN

∠BZN = ∠OZN - ∠BZO

Which gives;

∠BZN = 90° - 40° = 50°

  • The measure of angle ∠BZN =<u> 50°</u>

Learn more about tangents to a circle here:

brainly.com/question/14561226

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2 years ago
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