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Leni [432]
3 years ago
15

Draw the number line to represent.

Mathematics
1 answer:
Alekssandra [29.7K]3 years ago
6 0

Answer:

Mas não reconhecida como a face da sua vida

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The answer to your question is the inequality sign.
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3 years ago
I’ll mark youyou brainlist I’ll mark youyou brainlist
ale4655 [162]
8r + 206 + 7r +79 = 360
15r + 285 = 360
15r = 75
r = 5

7(5) + 79
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angle YMB is 114°
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3 years ago
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Subtract. Write your answer in simplest form.<br> 5/- 10/5
tigry1 [53]

Answer:

-1/10

Step-by-step explanation:

(5/(-10))/5 = -(5/10)/5 = 1/10

(Hopefully this helped you out!)

7 0
3 years ago
Given the following right triangle, find cose, sine, tane sececsce, and cote. Do not
IgorLugansk [536]

Step-by-step explanation:

Use the Pythagorean theorem:

leg^2+leg^2=hypotenuse^2

We have

leg=4,\ hypotenuse=10

Substitute:

4^2+leg^2=10^2

16+leg^2=100             <em>subtract 16 from both sides</em>

leg^2=84\to leg=\sqrt{84}\\\\leg=\sqrt{(4)(21)}\\\\leg=\sqrt4\cdot\sqrt{21}\\\\leg=2\sqrt{21}

sine=\dfrac{opposite}{hypotenuse}\\\\cosine=\dfrac{adjacent}{hypotenuse}\\\\tangent=\dfrac{opposite}{adjacent}\\\\cotangent=\dfrac{adjacent}{opposite}\\\\secant=\dfrac{hypotenuse}{adjacent}\\\\cosecant=\dfrac{hypotenuse}{opposite}

Substitute:

hypotenuse=10,\ opposite=4,\ adjacent=2\sqrt{21}

\sin\theta=\dfrac{4}{10}=\dfrac{2}{5}\\\\\cos\theta=\dfrac{2\sqrt{21}}{10}=\dfrac{\sqrt{21}}{5}\\\\\tan\theta=\dfrac{4}{2\sqrt{21}}=\dfrac{2}{\sqrt{21}}\cdot\dfrac{\sqrt{21}}{\sqrt{21}}=\dfrac{2\sqrt{21}}{21}\\\\\cot\theta=\dfrac{2\sqrt{21}}{4}=\dfrac{\sqrt{21}}{2}\\\\\sec\theta=\dfrac{10}{2\sqrt{21}}=\dfrac{5}{\sqrt{21}}\cdot\dfrac{\sqrt{21}}{\sqrt{21}}=\dfrac{5\sqrt{21}}{21}\\\\\csc\theta=\dfrac{10}{4}=\dfrac{5}{2}

5 0
3 years ago
0.04 is 10 times as great as which demcimal<br>​
Step2247 [10]

Answer:

0.004

Step-by-step explanation:

0.004 times 10 would be 0.04.

Hope this helps :)

6 0
3 years ago
Read 2 more answers
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