The circumference of the circle is 37.68 ft
Step-by-step explanation:
Given,
The area of the circle is 113.1 sq ft
To find the circumference of the circle we need to find the radius of the circle first
Formula
The area of circle with radius r is = π
sq unit
The circumference of circle with radius r is = 2πr unit
Let us take the radius of the circle is r ft
According to the problem,
π
or, 
or, 
or, r = 
or, r = 6
Now,
The circumference of the circle is 2×3.14×6 ft = 37.68 ft
Answer:
E-F and E-D
C-B and C-D
Step-by-step explanation:
The circle and triangle are as shown. The options are:
- A-B and C-B
- E-F and E-D
- E-D and C-D
- A-F and E-F
- C-B and C-D
By drawing radius lines from the center of the circle to the tangent points B, D, and F, we can divide the triangle into 3 kites. Therefore, only segments that are legs of the same kite are congruent. So the answer must be E-F and E-D, and C-B and C-D.
Answer:
B :step 2 she didnt collect all the like terms and calculate
Step-by-step explanation:
first rewrite remove all ( )Parentheses
2nd collect all like terms and calculate
a^4 + 7a -16 -12^a^3 + 5a -3
a^4 + 12a - 19 - 12a^3 ( Like terms are 7a +5a and -16 +-3)
so she skipped the second step
Unusual notation. I won't fuss with it.
a. We have isosceles PRT, so angle RPT = angle RTP.
By the definition of angle bisector, angle MTP = angle MTF, and angle MPT = angle MPU.
We have m angle RTP = m angle MTF + m angle MTP = 2 m angle MTP
Similarly, m angle RPT = 2 m angle MPT
2 m angle MTP = 2 m angle MPT
angle MPT = angle MPT
That's the first part.
b. That makes MPT isosceles.
c. 2x+124=180
2x = 56
x = 28 degrees
MTP = 28 degrees
d. We have angle RPT=angle RTP=56 so PRT=180-2(56)=68 degrees
PUT = 180 - UTP - UPT = 180 - 28 - 56 = 96 degrees
Bad drawing, PUT looks acute.
angle PRT = 68 degrees, angle PUT = 96 degrees
