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3 years ago

Which describes why the sun is a renewable resource?

1 answer:

7 0

it very often shines, it's always there ... but it is burning fuel, the fuel is itself ... so hoiw renewable is it over billions of years ?

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I need help with this one 2 if you guys don’t mind

zloy xaker [14]

3 is 3.81 meters

4 is 0.47 liters

5 is 4 cm

6 is 23 mm

7 is 53 m

8 is 1800 mg

9 is 31.07 mi

Hope I’m helping ya

6 0

4 years ago

Can anyone help me with this

Murrr4er [49]

Answer:

event s

Explanation:

the cow gets oxygen from the tree and proceeds to respirate.

8 0

3 years ago

The electric force between two charges A. increases with distance between the charges B. increases if either one of charges gets

beks73 [17]

Answer:

Option (A) , (b) and (d) are correct option

Explanation:

According to Coulomb's law electric force between two charges is given by

$F=\frac{1}{4\pi \epsilon _0}\frac{q_1q_2}{r^2}$

From the relation we can say that force is directly proportional to magnitude of charges and inversely proportional to distance between them '

So if we increase the distance then force will decrease

Increase if any of the charge get larger

If force is attractive then both the charge will be of different sign and is force is repulsive then both the charges of same sign

From above conclusion we can say that (a), (b) and (d) are correct option

6 0

3 years ago

The time period T of a simple pendulum is given by the relation

Vanyuwa [196]

Answer:

$T^2 \propto L$

Explanation:

The period of a simple pendulum is given by:

$T=2\pi \sqrt{\frac{L}{g}}$

where

L is the length of the pendulum

g is the acceleration of gravity

From this equation we can write

$T\propto \sqrt{L}\\T\propto \frac{1}{\sqrt{g}}$

Taking the square of this equation, we get:

$T^2 = (2\pi)^2 \frac{L}{g}$

So we see that $T^2$ is proportional to L and inversely proportional to g. So, we can write:

$T^2 \propto L\\T^2 \propto \frac{1}{g}$

So the only correct option is

$T^2 \propto L$

5 0

4 years ago

Read 2 more answers

At a stoplight, a truck traveling at 15 m/s passes a car as it starts from rest. The truck travels at constant velocity and the

Art [367]

The time that the car take to catch up to truck would be :

1/2 ar^2 = vt

1/2 (3) t^2 = 15t

1.5 t^2 = 15t

t ^2 = 10s

Hope this helps

4 0

4 years ago