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Korolek [52]
3 years ago
9

How far does an athlete travel at 10Km/hr in Half hour?

Physics
1 answer:
wariber [46]3 years ago
6 0
5 km because you just divide the hour by two to get half.
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Một nguồn O phát sóng cơ dao động theo phương trình u = 4cos(4pi t - pi/4). Tốc độ truyền sóng là 1m/s.
brilliants [131]

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3 years ago
What is an isotope ?
Step2247 [10]

<span>An isotope is a form of a chemical element whose atomic nucleus contains a specific number of neutrons in addition to the number of protons that distinctively defines the element. The nuclei of most atoms have neutrons as well as protons.</span>

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4 years ago
4) Write down the transformation of energy in torch light.<br>​
Elenna [48]

Answer:

<u>The transformation of energy in a torch light is as follows:</u>

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2) The electrical energy is converted into heat and light energy. (We feel the torch to be hot after some time and we can see the light energy)

Hope this helped!

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4 years ago
For copper, ρ = 8.93 g/cm3 and M = 63.5 g/mol. Assuming one free electron per copper atom, what is the drift velocity of electro
viktelen [127]

Answer:

V_d = 1.75 × 10⁻⁴ m/s

Explanation:

Given:

Density of copper, ρ = 8.93 g/cm³

mass, M = 63.5 g/mol

Radius of wire = 0.625 mm

Current, I = 3A

Area of the wire, A = \frac{\pi d^2}{4} = A = \frac{\pi 0.625^2}{4}

Now,

The current density, J is given as

J=\frac{I}{A}=\frac{3}{ \frac{\pi 0.625^2}{4}}= 2444619.925 A/mm²

now, the electron density, n = \frac{\rho}{M}N_A

where,

N_A=Avogadro's Number

n = \frac{8.93}{63.5}(6.2\times 10^{23})=8.719\times 10^{28}\ electrons/m^3

Now,

the drift velocity, V_d

V_d=\frac{J}{ne}

where,

e = charge on electron = 1.6 × 10⁻¹⁹ C

thus,

V_d=\frac{2444619.925}{8.719\times 10^{28}\times (1.6\times 10^{-19})e} = 1.75 × 10⁻⁴ m/s

4 0
3 years ago
Read 2 more answers
Why the efficiency of heat engine is always less than 100%​
valina [46]

Answer:

because some waste heat is always produced produced in a heat engine.

Explanation:

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7 0
3 years ago
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