The net force that is applied to the passenger during the elevator acceleration is 218.75 N.
<h3>What is net force?</h3>
This is the single force obtained from the combinatiion of two or more forces
To calculate the net force that is applied to the passenger during the elevator's acceleration, we use the formula below.
Formula:
- F = m(v-u)/t............ Equation 1
Where:
- F = force
- m = mass
- v = Final velocity
- u = initial velocity
- t = time.
From the question,
Given:
- m = 70 kg
- u = 0 m/s
- v = 12.5 m/s
- t = 4 s
Substitute these values into equation 1
Hence, The net force that is applied to the passenger during the elevator acceleration is 218.75 N.
Learn more about net force here: brainly.com/question/13370981
Answer:
I = W / 4π R_{s}², P = W / 2π c R_{s}², Io /I_{earth} = 10⁴
Explanation:
The intensity is defined as the ratio between the emitted power and the area of the spherical surface
I = P / A
Since the emitted power is constant and has a value of W for this case, let's look for the area of the sphere on the surface of the sun
A = 4π
²
I = W / 4π R_{s}²
.- The radiation pressure for total absorption is
P = S / c
Where S is the Pointer vector that is equal to the intensity
Let's replace
P = W / 2π c R_{s}²
.- We repeat for r = R_{s}/2
I₂ = W / 4π (R_{s}/ 2)²
I₂ = 4 W / 4π R_{s}²
I₂ = 4 Io
I₀ = W / 4piRs2
We calculate the radiation pressure
P₂ = I₂ / c
P₂ = 4 I₀ / c
P₂ = 4 (W / 4pi c Rs2)
.- the relationship between these magnitudes is
I₂ / I₀ = 4
P₂ / P₀ = 4
Let's calculate the intensity on the surface where the Earth is
r = 1.50 10¹¹ m
= W / 4π r²
Io / I_{earth} = r² /
²
Io /I_{earth} = (1.5 10¹¹ / 6.96 10⁸) 2
Io /I_{earth} = 4.6 10⁴
Io /I_{earth} = 10⁴
To answer this you multiply the N (which is 300 in this case) by m (or 5). This will give you 1500
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