Joe says that the following statement is true. Do you agree? Explain. 4×3)3+5-10=4×3+5-10
1 answer:
You might be interested in
Answer:
(i)23.77kg
(ii)(ii) the inequality 20≤t≤48 means the weight of the dogs determined is for dogs that have the age of 20 weeks or less to the age of 48 weeks not more.
(iii)44 weeks
(iv)0.92
(v)Attached
(vi)The value of weight will be negative,which is unrealistic.
Step-by-step explanation:
(i)Given that the weight is modeled by the equation;
w = 0.92t−0.15 (20 ≤ t ≤ 48)
then substitute the value of t in the equation given that t=26 weeks
w=0.92*26-0.15=23.77kg
(ii) the inequality 20≤t≤48 means the weight of the dogs determined is for dogs that have the age of 20 weeks or less to the age of 48 weeks not more.
(iii)Apply the equation for weight
w=0.92t-0.15
40=0.92t-0.15
40+0.15=0.92t
40.15=0.92t
40.15/0.92=t
43.6⇒⇒44 weeks
(iv) Here , write the equation in slope intercept form of y=mx+c where m is the slope and c is the y-intercept
w=0.92t-0.15
y=mx+c
m=0.92
(v)sketch attached
(vi)
At birth, t=0 hence to find weight
w=0.92t-0.15
w=0.92*0-0.15
w=0-0.15
w=-0.15
The model cannot be extended to model accurately the dog's weight at birth because you will get a negative value for weight which is not realistic.
