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Gnesinka [82]
3 years ago
15

Find the nth term of the sequence: 9, 4, -1, -6, -11,.............

Mathematics
1 answer:
Elan Coil [88]3 years ago
7 0

Answer:

-15

Step-by-step explanation:

goes down -5 each time

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A tank full of water is leaking at a constant rate for 15 minutes. The equation
kupik [55]

Answer:

C. There were 500 liters in the tank when the leak started, and it is decreasing by 8 liters per minute.

Step-by-step explanation:

-8x is the rate of the leak and 500 is the initial value for water in the tank.

6 0
2 years ago
Mentioneaza rolul indicatiei scenei : vrea sa para nepasator
melomori [17]

Answer:

hi

Step-by-step explanation:

7 0
3 years ago
What is the conversion?
Gelneren [198K]

Answer:

  see below

Step-by-step explanation:

The conversion factor in the box is the product ...

  \dfrac{1\,\text{kPa}}{1000\,\text{Pa}}\cdot\left(\dfrac{1\,\text{m}}{100\,\text{cm}}\right)^3=10^{-9}\,\dfrac{\text{kPa m}^3}{\text{Pa cm}^3}

_____

The purpose of a conversion factor is to multiply by 1 in the form of a ratio that changes the units. We know that 1000 Pa = 1 kPa, so the ratio (1 kPa)/(1000 Pa) is the ratio of two equal quantities. It has the value 1 and will change units from Pa to kPa.

Likewise, 100 cm = 1 m, so (1 m)/(100 cm) will change the units from cm to m. However the given expression uses cm³, so we need to multiply by the conversion factor 3 times. That factor is ((1 m)/(100 cm))³ = (1 m³)/(10⁶ cm³).

To choose the appropriate conversion factor, look at the units you have (Pa, cm) and the units you want (kPa, m). Find the relationship these have to each other, and write the ratio so that it will cancel the units you have and leave the units you want.

When SI units are involved the prefixes help you out. k = kilo = 1000; c = centi = 1/100. It is worthwhile to get to know them.

8 0
3 years ago
Can anyone help me out in my homework. I would love to talk about these problems ​
katen-ka-za [31]

Step-by-step explanation:

(b) If F_G = m_1g, then

m_1g = G\dfrac{m_1m_2}{r^2}

Note that m_1 cancel out so we get

g = G\dfrac{m_2}{r^2}

Solving for m_2, we get

m_2 = \dfrac{gr^2}{G}

(c) I'm not sure what the problem is asking for but here goes. As r doubles, F_G becomes

F_G = G\dfrac{m_1m_2}{(2r)^2} = \dfrac{1}{4}\left(G\dfrac{m_1m_2}{r^2}\right)

5 0
3 years ago
If arc AE = 64° and arc BD = 20°, find the measure of angle BCD.
tamaranim1 [39]
Angle mes BCD = (mes Arc AE-mes ARC BD)/2


Plug: mes BCD = (64+20)/2 = 44° (Number C)
5 0
3 years ago
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