The area of a square is expressed as the length of the side to the power of two, A = s^2. We were given the area of the enlarged photo which is 256 in^2. Also, it was stated that the length of the enlarged photo is the length of the original photo plus ten inches. So, from these statements we can make an equation to solve for x which represents the length of the original photo.
A = s^2
where s = (x+10)
A = (x+10)^2 = 256
Solving for x,
x= 6 in.
The dimensions of the original photo is 6 x 6.
Answer:
it is 30.5
Step-by-step explanation:
(3X+4Y):2
(3×7+4×10):2
(21+40):2
61:2
30.5
The surface is parameterized by
and the normal to the surface is given by the cross product of the partial derivatives of 
:
It looks like you're given
Then the normal vector is
Now, the point (2, 2, 0) corresponds to u and v such that
and solving gives 
, so the normal vector at the point we care about is
Then the equation of the tangent plane is
A. 18
Formula for area is LxW.
Divide 144 by 8 and you get 18.
