Ask question

Ask question

All categories

4 years ago

14

Find the sum of (6d+5)-(2-3d)

1 answer:

Andrew [12]4 years ago

5 0

Note the subtraction sign. Distribute the negative sign to all terms within the second equation.

6d + 5 - 2 +3d

Combine like terms

6d + 3d + 5 - 2

9d + 3

9d + 3 is your answer

Hope this helps

You might be interested in

Factor 5x2 + 28x – 12.

Masja [62]

Not sure whether the (x) in the first half of the equation refers to Multiply or x so jyst going to assume.

2(5x)+28x-12
= 2(5x+14x-6)
=2(19x-6)

6 0

4 years ago

Read 2 more answers

What is the approximate area of the circle? Use A. 17.6 square inches B. 24.6 square inches C. 35.2 square inches D. 98.5 square

anygoal [31]

There should have been an attached image.

Area of a circle is can only be computed when the radius or diameter is provided.

Area of a circle = π r²

Based on the image I saw, the radius is 5.6 inches

A = 3.14 * (5.6in)²
A = 3.14 * 31.36 in²
A = 98.47 in² ⇒ CHOICE D. 98.5 square inches.

6 0

3 years ago

Illl ask again can someone help me

guajiro [1.7K]

Hiiiii

This is the answer

Hope it's help

3 0

3 years ago

Read 2 more answers

The longest side of an acute triangle measures 30 inches. The two remaining sides are congruent, but their length is

qwelly [4]

Answer:

(C)72.4 in

Step-by-step explanation:

Given an acute triangle in which the longest side measures 30 inches; and the other two sides are congruent.

Consider the attached diagram

AB=BC=x

However to be able to solve for x, we form a right triangle with endpoints A and C.

Since the hypotenuse is always the longest side in a right triangle

Hypotenuse, AC=30 Inches

Using Pythagoras Theorem

$30^2=x^2+x^2\\900=2x^2\\x^2=450\\x=\sqrt{450}\\x=21.21$ inches$

Therefore, the smallest possible perimeter of the triangle

Perimeter=2x+30

=2(21.21)+30

=42.42+30

=72.4 Inches (rounded to the nearest tenth)

4 0

3 years ago

Which are the roots of the quadratic function f(q) = q2 – 125? Check all that apply. q = 5 q = –5 q = 3 q = –3 q = 25 q = –25

slamgirl [31]

Answer:

The given options are not roots of q(x)

Step-by-step explanation:

$f(q)= q^2-125$

To find the roots of the given quadratic equation

we replace f(q) with 0 and solve for q

$0= q^2-125$

Add 125 on both sides

$125= q^2$

take square root on both sides

$q=+-5\sqrt{5}$

$q=+5\sqrt{5}$ and $q=-5\sqrt{5}$

The given options are not roots of q(x)

7 0

3 years ago

Read 2 more answers