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Pavlova-9 [17]
3 years ago
8

Line plotting (will give brainiest bc im feeling nice today)

Mathematics
2 answers:
Mazyrski [523]3 years ago
7 0
I would plot it at the 7th line of the number line.
It seems like the origin 1 4/5 and 1 away from that is the 4/5 mark on the number line

B. Put point E on the 4th mark on the number line
aliya0001 [1]3 years ago
4 0

Answer:

A.) If the origin is 0, then point c should be three lines to the right of 1 1/3 at number 1.

B.) 1/5

Step-by-step explanation:

Not completely sure if this is correct since im not postive of what its asking

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Joshua traveled 5 hours from City A to City B. The distance between the cities is 260 miles. First he traveled at the constant s
ruslelena [56]

Joshua  travelled for 3 hours at the constant speed of 60 mi/h

<h3><u>Solution:</u></h3>

Given that, Joshua traveled 5 hours from City A to City B

The distance between the cities is 260 miles.  

First he traveled at the constant speed of 40 mi/h, and then at the constant speed of 60 mi/h.  

So, let the number of hours he travelled with 40 mi/h be "n" hours and the distance travelled be "x" miles

Then, the time in which he travelled with 60 mi/h will be 5 – n hours and distance travelled will be 260 – x miles

We have to find how many hours did he travel at the constant speed of 60 mi/h

<em><u>The relation between speed and distance is given as:</u></em>

\text { distance }=\text { speed } \times \text { time. }

\begin{array}{l}{40 \mathrm{mil} / \mathrm{h} \times \mathrm{n} \text { hours }= x \text { miles }} \\\\ {\rightarrow x=40 \mathrm{n} \rightarrow(1)} \\\\ {\text { And } 60 \times(5-\mathrm{n})=260-x \text { miles }}\end{array}

\begin{array}{l}{\rightarrow 300-60 n=260-40 n(\text { from }(1))} \\\\ {\rightarrow 60 n-40 n=300-260} \\\\ {\rightarrow 20 n=40} \\\\ {\rightarrow n=2}\end{array}

So, he travelled 2 hours with speed of 40 mi/h and 5 – 2 = 3 hours with speed of 60 mi/h

Hence, he travelled for 3 hours

5 0
3 years ago
Parallel lines r and s are cut by two transversals, parallel lines t and u. Lines r and s are crossed by lines t and u to form 1
Katena32 [7]

Answer:

5 and 13

Step-by-step explanation:

I got it right on edge

3 0
3 years ago
Read 2 more answers
Given circle O, angle A has a measure of 36° and the radius is 10 cm, find the area of sector BOC.
Fed [463]

Answer:

The area of the sector BOC is A' = 31.4 cm^{2}

Step-by-step explanation:

Radius of the circle = 10 cm = 0.1 m

Angle of sector \theta = 36°

Area of the circle A = \pi r^{2}

A = 3.14 × 0.1^{2} = 0.0314 m^{2}

Now area of the sector BOC is

A' = A (\frac{\theta}{360} )

A' = 0.0314 (\frac{36}{360} )

A' = 0.00314  m^{2} = 31.4 cm^{2}

Therefore the area of the sector BOC is A' = 31.4 cm^{2}

7 0
4 years ago
Guys plz help i’m struggling
Blababa [14]

Answer:

0.46017

Step-by-step explanation:

Given :

Mean score = 75

Standard deviation, s = 10

Areum's score = 76

Probability of scoring higher than Areum is given by :

P(x > 76)

The standardized score : (x - mean) / standard deviation

P(x > 76) = P[Z > (76 - 75) / 10]

P[(Z > 0.1)] = 0.46017 (Z probability calculator)

= 0.46017

4 0
3 years ago
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PolarNik [594]
How there’s nothing to see we can’t see anything
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3 years ago
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