Answer:
not visible....
Step-by-step explanation:
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If A=w(50-w)
A=50w-w^2
dA/dw=50-2w
d2A/dw2=-2
Since the acceleration is a constant negative, that means that when velocity, dA/dw=0, it is at an absolute maximum for A(w)...
dA/d2=0 only when 50=2w, w=25
So as the case with any rectangle, the perfect square will enclose the greatest area possible with respect to a given amount of material to enclose that area...
So the greatest area occurs when W=L=25 in this case:
A(25)=50w-w^2
Area maximum is thus:
Amax=50(25)-(25)^2=625 u^2
Answer:
pretty sure is it B. -1.75 and 4 but not 100% positive
This describes a parabolic path that starts at x=0 on a value of y = -5.1. That's when the rock is below ground in the hole. To find the answer we need to know the second x axis crossing. The first is when it is rising and reaches ground level, the second is after it peaks and falls back to the ground and lands. Using the quadratic formula I get the two zeros of this function to be about
x= 15.29, and 66.71. The rock then lands 66.71 feet from him horizontally.
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Answer: 
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How to get this answer:
Use the unit circle to note that 
when 
(aka 45 degrees)
Beyond this point, cosine is smaller than sine. This means that anything from 0 to pi/4 will have sine be smaller than cosine. It might help to graph y = sin(x) and y = cos(x) on the interval from x = 0 to x = pi.
The two curves y = sin(x) and y = cos(x) intersect at the point 
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Here's a more detailed picture of whats going on.
Intersect the intervals 
and 
and you'll end up with the final answer
