Answer:
y=1.2x-3
Step-by-step explanation:
I had this as an rsm problem a few weeks ago and forgot how to solve it lol hope this helps
The answer is 2/3 I hope it helped
Answer:the car was traveling at a speed of 80 ft/s when the brakes were first applied.
Step-by-step explanation:
The car braked with a constant deceleration of 16ft/s^2. This is a negative acceleration. Therefore,
a = - 16ft/s^2
While decelerating, the car produced skid marks measuring 200 feet before coming to a stop.
This means that it travelled a distance,
s = 200 feet
We want to determine how fast the car was traveling (in ft/s) when the brakes were first applied. This is the car's initial velocity, u.
Since the car came to a stop, its final velocity, v = 0
Applying Newton's equation of motion,
v^2 = u^2 + 2as
0 = u^2 - 2 × 16 × 200
u^2 = 6400
u = √6400
u = 80 ft/s
Answer:
2.547 = x
Step-by-step explanation:
tan 23 = x/6 Use this equation to find the value of x
0.4245 = x/6 Multiply both sides by 6
2.547 = x
Answer:
That's not a subtractive equation, the symbol that you used indicates that it is an addition equation. if the question was 1-1 then the answer wouldn't be 2 but since the question is 1+1 the answer is 2
Step-by-step explanation:
