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3 years ago

13

Amanda reads 300 pages in 10 hours. If each page has 200 words on it, how many words did Amanda read per minute?

2 answers:

puteri [66]3 years ago

7 0

Answer:

100

Step-by-step explanation:

So if there is 200 word per page it will be 200×300, which is 60,000. We are trying to find words per minute, so we do; 10×60 (1 hour=60minutes) which is 600. so to find the words per minute we do:

60,000÷600=100

ICE Princess25 [194]3 years ago

5 0

Answer:

so that means you would divide 300 by 10 and that means she reads 30 pages in 1 hour so if you do 30 divided by 60 or 1 hour you get 0.5 pages so she reads 100 words in 1 minutes

Step-by-step explanation:

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Convert 75 degrees to radican measure

NeX [460]

Answer:5π/12

Step-by-step explanation:

180°=π

75°=x

x=75π ➗ 180

x=5π/12

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3 years ago

The real number square root of 16 belongs to which sets of numbers?

klasskru [66]

Answer: Square root of 16 is +4 or -4. Since -4 is not a natural number, the square root can be described as an integer.

Step-by-step explanation:

The square root of 16 is a rational number. The square root of 16 is 4, an integer

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3 years ago

In a 4x4x4 cube, the face is painted red, then divided into 64 1x1x1 cubes. How many of the 1x1x1 cubes are painted 1 or 2 faces

WITCHER [35]

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3 years ago

Read 2 more answers

What is the greatest common factor of 44c5,22c3 and 11c4?

elena-s [515]

Answer:

The greatest common factor of the given expressions is

$11c^3$

Step-by-step explanation:

Given that $44c^5,22c^3,11c^4$

$44c^5$ can be written as

$11\times 4\times c^3\times c^2$

$22c^3$ can be written as

$11\times 2\times c^3$

and $11c^4$ can be written as

$11\times 1\times c^3\times c$

Comparing the common factors we have $11\times c^3$ is the greatest common factor of $44c^5,22c^3,11c^4$

Therefore the greatest common factor of the given expressions is

$11c^3$

3 0

3 years ago

Write one digit on each side of 23 to make a four digit multiple of 72. How many different solutions does this problem have?

user100 [1]

Answer:

This problem has two possible solutions.

2232

7236

Step-by-step explanation:

To be divisible by 72, a number has:

To be divisible by both 8 and 9 at the same time.

It is divisible by 8 if it's last two digits are divisible by 4.

It is divisible by 9 it the sum of it's digits is a number divisible by 9.

a23b

3b must be divisible by 4. In the thirties, the numbers that are divisible by 4 are 32 and 36. So b = 2 or b = 6.

a232

2 + 3 + 2 = 7

The higest possible value of a is 9 and the lowest is 1.

Between 8 and 16, only 9 is divisible by 9. So a = 2.

a = 2, b = 2 is one of the solutions.

a236

2 + 3 + 6 = 11

The higest possible value of a is 9 and the lowest is 1.

Between 12 and 20, only 18 is divisible by 9. So we need a = 7

5 0

3 years ago