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jek_recluse [69]
3 years ago
14

Rozwiąż równanie kwadratowe: 3/4 y^2 +9=y/2+(y-3)^2

Mathematics
1 answer:
lutik1710 [3]3 years ago
5 0
Najpierw rozszerz po prawej strony równania.

\dfrac34y^2+9=\dfrac y2+(y-3)^2\implies\dfrac34y^2+9=\dfrac y2+y^2-6y+9

Przenieść wszystko na jedną stronę i uproszcz.

\dfrac{y^2}4-\dfrac{11y}2=0

Rozkładaj lewą stronę na czynniki.

\dfrac14y(y-22)=0

Są dwa rozwiązania,

y=0\text{ i }y=22
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