Given:ABCD is a rhombus.
To prove:DE congruent to BE.
In rombus, we know opposite angle are equal.
so, angle DCB = angle BAD
SINCE, ANGLE DCB= BAD
SO, In triangle DCA
angle DCA=angle DAC
similarly, In triangle ABC
angle BAC=angle BCA
since angle BCD=angle BAD
Therefore, angle DAC =angle CAB
so, opposite sides of equal angle are always equal.
so,sides DC=BC
Now, In triangle DEC and in triangle BEC
1. .DC=BC (from above)............(S)
2ANGLE CED=ANGLE CEB (DC=BC)....(A)
3.CE=CE (common sides)(S)
Therefore,DE is congruent to BE (from S.A.S axiom)
Washington D.C is the capital of the US
For this case we have to by definition:
1 kg equals 1000 grams
Shark 1:
405 kg and 68 grams
Thus, shark 1 weighs 405,068 grams.
Shark 2:
324 kg and 75 grams
Thus, shark 2 weighs 324,075 grams.
Subtracting we have:
Thus, shark 1 weighs 80,993 grams more than the second.
Answer:
Shark 1 weighs 80,993 grams more than the second.
