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Lyrx [107]
3 years ago
13

A crossbow is fired horizontally off a cliff with an initial velocity of 15 m/s. If the arrow takes 4s to hit the ground, what i

s the range of the projectile?
Physics
1 answer:
omeli [17]3 years ago
5 0

Answer:

The range of the projectile is 60 meters

Explanation:

To determine the range/distance of the projectile, the formula for velocity is used;

velocity = distance/time

where velocity is 15 m/s

time is 4 seconds

distance is unknown

From the formula above, distance is made the subject and thus

distance = velocity × time

distance = 15 × 4

distance = 60 m

The range of the projectile is 60 meters

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A planar electromagnetic wave is propagating in the +x direction. At a certain point P and at a given instant, the electric fiel
jeka94

Answer:

B=2.74\times 10^{-10}\ T

Explanation:

It is given that,

A planar electromagnetic wave is propagating in the +x direction.The electric field at a certain point is, E = 0.082 V/m

We need to find the magnetic vector of the wave at the point P at that instant.

The relation between electric field and magnetic field is given by :

c=\dfrac{E}{B}

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B=\dfrac{E}{c}\\\\B=\dfrac{0.082}{3\times 10^8}\\\\B=2.74\times 10^{-10}\ T

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3 0
3 years ago
The position-time equation for a certain train is
astraxan [27]

Answer:

a=4.8m/s^2

Explanation:

Hello,

In this case, since the acceleration in terms of position is defined as its second derivative:

a=\frac{d^2x(t)}{dt^2}=\frac{d^2}{dt^2}(2.9+8.8t+2.4t^2)

The purpose here is derive x(t) twice as follows:

a=\frac{d^2x(t)}{dt^2}=\frac{d}{dt}(8.8+2*2.4*t)\\ \\a=4.8m/s^2

Thus, the acceleration turns out 4.8 meters per squared seconds.

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8 0
4 years ago
What is the electrical force between q2 and q3? recall that k = 8.99 × 109 n•meters squared over coulombs squared.. 1.0 × 1011 n
max2010maxim [7]

The magnitude of the electrical force between q2 and q3 is given as a ratio between the product of their charges and the square of the distance of separation.

<h3>What is the magnitude of electrical forces between two charges?</h3>

The magnitude of the electrical force between two charges refers to the attractive or repulsive forces that exists between two charges separated by a given distance in an electric field.

The magnitude of the electrical force, F between the two charges q2 and q3 is given be my the formula below

F = \frac{K \times q_2 \times q_3}{d^{2}}

Therefore, the magnitude of the electrical force between q2 and q3 is given as a ratio between the product of their charges and the square of the distance of separation.

Learn more about electrical force at: brainly.com/question/17692887

#SPJ4

6 0
2 years ago
When an earthquake occurs, two types of sound waves are generated and travel through the earth. The primary, or P, wave has a sp
Zielflug [23.3K]

Answer:d=7.94\times 10^5\ m

Explanation:

Given

Speed of Primary wave v_1=8\ km/s

Speed of secondary wave v_2=4.5\ km/s

difference in timing of two waves are 77.2\ s

Suppose both travel a distance of d km then

t_1=\frac{d}{8}\quad \ldots (i)

t_2=\frac{d}{4.5}\quad \ldots (ii)

Subtract (ii) from (i)

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d[\frac{1}{4.5}-\frac{1}{8}]=77.2

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d=794.23\ km

d=7.94\times 10^5\ m

7 0
3 years ago
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