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Lyrx [107]
2 years ago
13

A crossbow is fired horizontally off a cliff with an initial velocity of 15 m/s. If the arrow takes 4s to hit the ground, what i

s the range of the projectile?
Physics
1 answer:
omeli [17]2 years ago
5 0

Answer:

The range of the projectile is 60 meters

Explanation:

To determine the range/distance of the projectile, the formula for velocity is used;

velocity = distance/time

where velocity is 15 m/s

time is 4 seconds

distance is unknown

From the formula above, distance is made the subject and thus

distance = velocity × time

distance = 15 × 4

distance = 60 m

The range of the projectile is 60 meters

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If Chris throws the baseball 60 meters forward in 4.2 sec, what is the velocity of the ball? I need answer immediately
vazorg [7]

Answer:

14.3 m/s

Explanation:

velocity equation

v= d/t

v= 60/4.2

v=14.28

round it to 1 decimal place

v= 14.3m/s

5 0
2 years ago
What are two factors<br> affecting friction? How do<br> they affect friction?<br> ch
AlexFokin [52]
The roughness of the surface, the mass of the object, and the area of contact.
5 0
3 years ago
A 2,537-kg truck moving at 14 m/s strikes a car waiting at a traffic light, hooking bumpers. The two continue to move together a
slavikrds [6]

Answer:

1902.75 kg

Explanation:

From Law of conservation of momentum,

m₁u₁ + m₂u₂ = V (m₁ + m₂).................... Equation 1

make m₂ the subject of the equation,

m₂ = (m₁V - m₁u₁)/(u₂-V)..................... Equation 2

Where m₁ = mass of the truck, m₂ = mass of the car, u₁ initial velocity of the truck, u₂ = initial velocity of the car V = common velocity

Given: m₁ = 2537 kg, u₁ = 14, V= 8 m/s, u₂ = 0 m/s ( as the car was at rest waiting at a traffic light)

Substituting into equation 2.

m₂ =[2537(8) - 2537(14)]/(0-8)

m₂ = (20296-35518)/-8

m₂ = -15222/-8

m₂ = 1902.75 kg.

Thus the mass of the car = 1902.75 kg

5 0
3 years ago
The mass of the Earth is 5.972 × 10^27 g. Convert this mass to kg.
sineoko [7]

Answer:

5.972x10^27 x 10^-3 = 5.972x10^24

Explanation:

1g = 10^-3 kg => So the mass of Earth in kg is 5.972x10^24

3 0
2 years ago
How much work is done (by a battery, generator, or some other source of potential difference) in moving Avogadro's number of ele
konstantin123 [22]

Answer:

-1486 KJ

Explanation:

The work done by an electric field on a charged body is:

W = ΔV * q

where ΔV = change in voltage

q = total charge

The total charge of Avogadro's number of electrons is:

6.0221409 * 10^(23) * -1.6023 * 10^(-19) = -9.65 * 10^(4)

The change in voltage, ΔV, is:

9.20 - (6.90) = 15.4

Therefore, the work done is:

W = -9.65 * 10^(4) * 15.4 = -1.486 * 10^6 J = -1486 KJ

The negative sign means that the motion of the electrons is opposite the electrostatic force.

5 0
2 years ago
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