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Sladkaya [172]
4 years ago
8

Give two examples of direct current electricity.​

Physics
1 answer:
ludmilkaskok [199]4 years ago
6 0

Answer:

<h3>Ion beams and Electrochemical are two examples of direct current electricity.</h3>
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The driver or a sports car traveling at 10 m/s steps down hard on the accelerator for 5 seconds. If they accelerate at a rate of
ivanzaharov [21]

Answer:

53.125m

Explanation:

The displacement of the car, denoted by S, can be calculated using the formula:

S = ut + 1/2at²

Where;

u = initial velocity/speed (m/s)

t = time (s)

a = acceleration (m/s²)

According to the information provided in this question, u = 10m/s, t = 5s, a = 0.25m/s², S = ?

S = ut + 1/2at²

S = (10 × 5) + 1/2 (0.25 × 5²)

S = 50 + 1/2 (0.25 × 25)

S = 50 + 1/2(6.25)

S = 50 + 3.125

S = 53.125m

4 0
3 years ago
Does the number of particles change as the substance changes its state?​
Leviafan [203]

Particles stay the same unless there is a chemical change whether the matter is solid, liquid or gas. ... When substances change state there is no change in mass so if 100 g of ice is melted 100g of water are formed this will boil to form 100g of steam (this is called "conservation of mass").

4 0
3 years ago
MIT’s robot cheetah can jump over obstacles 46. cm high and has speed of 12.0 km/h. a) If the robot launches itself at an angle
labwork [276]

Answer:

(a)  y_{max}=0.423m

(b)  \alpha =64.3^{o}

Explanation:

Given data

v_{i}=12km/h=3.33m/s\\\alpha =60^{o}\\g=9.8m/s^{2}\\Required\\(a)y_{max}\\(b)Angle

Solution

For Part (a)

As the velocity component in direction of y is given by:

v_{yi}=v_{i}Sin\alpha \\v_{yi}=3.33Sin60\\v_{yi}=2.88m/s

The maximum displacement is given by:

v_{yf}^{2}=v_{yi}^{2}-2gy_{max}\\ y_{max}=\frac{(2.88)^{2}}{2(9.8)}\\ y_{max}=0.423m

For Part (b)

To reach y=46cm =0.46m apply:

0=v_{yi}^{2}-2(9.8)(0.46)\\v_{yi}=3m/s\\As\\Sin\alpha =\frac{v_{yi}}{v_{i}}\\\alpha  =Sin^{-1}(\frac{v_{yi}}{v_{i}})\\\alpha =Sin^{-1}(\frac{3}{3.33} )\\\alpha =64.3^{o}

5 0
3 years ago
Read 2 more answers
A ships initial position is 25 km east of the origin. What is the ship’s final position if it sails at a constant velocity of 42
Evgen [1.6K]

Answer:

88km E

Explanation:

25 km is added already

then if we take the formula of speed(V)

V=d/t

and rearrange it to subject d (distance)

d= V x t

we get

d= 42km/h x 1.5hrs

we get

63 km

now if we add the already travelled 25 km to this additional distance

63km + 25km = 88km

Thus the final distance traversed by the ship from its origin is

88km E

Plz mark me brainliest

Hope this helps

7 0
3 years ago
If an object is not moving, the forces acting upon it are...
postnew [5]
It A Thanos:”Balanced”
7 0
3 years ago
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